Network Elements and the Concept of Circuit
- Calculate the value of R in ohms under maximum power transfer condition for the circuit shown below—
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From above figure, if we apply maximum power transfer theorem, then
RL = Rth = 20|| Ror RL = 20R 20 + R or 16 = 20R 20 + R
or R = 80Ω
However, the maximum power will transfer if and only if R = 0, so that there is no voltage drop in internal resistances. Therefore alternative (B) is the correct choice.Correct Option: B
From above figure, if we apply maximum power transfer theorem, then
RL = Rth = 20|| Ror RL = 20R 20 + R or 16 = 20R 20 + R
or R = 80Ω
However, the maximum power will transfer if and only if R = 0, so that there is no voltage drop in internal resistances. Therefore alternative (B) is the correct choice.
- For the circuit arrangement shown below. Calculate the value of R under maximum power transfer condition—
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From above figure it is clear that under maximum power transfer condition R should be equals to zero ohm. Hence alternative (C) is the correct choice.Correct Option: C
From above figure it is clear that under maximum power transfer condition R should be equals to zero ohm. Hence alternative (C) is the correct choice.
- The power delivered by element 3 in figure shown below is—
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From given figure
Power absorbed by element 1 & 2 = [2 × 5 + 2 × 20] = – 50W
Thus the element 3 absorbs 50W of power or, equivalently, delivers 50 W.Correct Option: B
From given figure
Power absorbed by element 1 & 2 = [2 × 5 + 2 × 20] = – 50W
Thus the element 3 absorbs 50W of power or, equivalently, delivers 50 W.
- Calculate the equivalent resistance at terminal A and B—
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where, RCD or REF = 25 || 50 || 50 = 12.5 Ω
RAB = 4 + 6 + 12.5 = 22.5 Ω
Hence alternative (B) is the correct choiceCorrect Option: B
where, RCD or REF = 25 || 50 || 50 = 12.5 Ω
RAB = 4 + 6 + 12.5 = 22.5 Ω
Hence alternative (B) is the correct choice
- D.C. component of the waveform shown below is—
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D.C. component = 1 f(t) dt T T = 1 1 2 dt + 2 0.dt + 4 – 2 dt + 5 0 dt 5 0 1 1 4 = 1 [2 + 0 + (– 8 + 4) + 0] µA 5 = –2 = – 0.4 µA 5 Correct Option: B
D.C. component = 1 f(t) dt T T = 1 1 2 dt + 2 0.dt + 4 – 2 dt + 5 0 dt 5 0 1 1 4 = 1 [2 + 0 + (– 8 + 4) + 0] µA 5 = –2 = – 0.4 µA 5