196. The current having the waveform shown in figure is flowing in a resistance of 10Ω. The average power is—
     
     
     

1. 1. 1000 watt

   
   
   

   2. 1000/2 watt

   
   
   

   3. 1000/3 watt

   
   
   

   4. 1000/4 watt

   
   
   

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1. View Hint View Answer Discuss in Forum

   Average Power =		1	10(10t)2dt		R
   		1

   
   

   [By using formula avg. power		1	T0I2dt		.R ]
   		T

   
   

   = 100		T0I2dt		× 10

   
   

   = 1000		I3		10
   		3

   
   

   = 1000 ×	1	=	1000	watt
   	3		3

   
   

   Correct Option: C

   Average Power =		1	10(10t)2dt		R
   		1

   
   

   [By using formula avg. power		1	T0I2dt		.R ]
   		T

   
   

   = 100		T0I2dt		× 10

   
   

   = 1000		I3		10
   		3

   
   

   = 1000 ×	1	=	1000	watt
   	3		3

   
   

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197. The equivalent resistance as seen between the terminals (a, b) is—

1. 1. 2 Ω

   
   
   

   2. 4 Ω

   
   
   

   3. 1 Ω

   
   
   

   4. Not possible

   
   
   

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1. View Hint View Answer Discuss in Forum

   R_ab = 1 + (2 || R_ab)
   

   RAB = 1 +	2.Rab
   	2 + Rab

   
   

   RAB = 1 +	2 + Rab + 2 Rab
   	2 + Rab

   
   2 R_ab + (R_ab) ² = 2 + R_ab + 2 R_ab
   (R_ab)² – R_ab – 2 = 0
   R² _ab – 2 R_ab + R_ab – 2 = 0
   R_ab (R_ab – 2) + 1 (R_ab – 2) = 0
   (R_ab + 1) (R_ab – 2) = 0
   R_ab = – 1, 2
   R_ab = – 1 not possible
   so R_ab = 2

   
   

   Correct Option: A

   R_ab = 1 + (2 || R_ab)
   

   RAB = 1 +	2.Rab
   	2 + Rab

   
   

   RAB = 1 +	2 + Rab + 2 Rab
   	2 + Rab

   
   2 R_ab + (R_ab) ² = 2 + R_ab + 2 R_ab
   (R_ab)² – R_ab – 2 = 0
   R² _ab – 2 R_ab + R_ab – 2 = 0
   R_ab (R_ab – 2) + 1 (R_ab – 2) = 0
   (R_ab + 1) (R_ab – 2) = 0
   R_ab = – 1, 2
   R_ab = – 1 not possible
   so R_ab = 2

   
   

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198. The Nodal method of circuit analysis is based on—

1. 1. KVL and Ohm's law

   
   
   

   2. KCL and Ohm's law.

   
   
   

   3. KCL and KVL

   
   
   

   4. KCL, KVL and Ohm's law

   
   
   

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1. View Hint View Answer Discuss in Forum

   Nodal circuit analysis method is based on KCL and Ohm's law.

   Correct Option: B

   Nodal circuit analysis method is based on KCL and Ohm's law.

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199. Twelve 1H inductors are used as edge to form a cube. The inductance between two diagonally opposite corners of cube is—

1. 1. 5	H
      6

   
   
   

   2. 10	H
      6

   
   
   

   3. 2 H

   
   
   

   4. 3	H
      2

   
   
   

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1. View Hint View Answer Discuss in Forum

   Apply same concept as done in the earlier problem.

   Correct Option: A

   Apply same concept as done in the earlier problem.

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200. Twelve 1Ω resistors are used as edge to form a cube. The resistance between two diagonally opposite corners of the cube is—

1. 1. 5	Ω
      6

   
   
   

   2. 6	Ω
      5

   
   
   

   3. 1 Ω

   
   
   

   4. None of these

   
   
   

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1. View Hint View Answer Discuss in Forum

   Suppose value of resistances be RΩ each. Applying KVL by selecting any path between A and B.
   

   VAB =	1	. R +	1	R +	1	R
   	3		6		3

   
   

   VAB = IR		5
   		6

   
   

   VAB	=	5R
   I		6

   
   

   or RAB =	5R
   	6

   
   where R = 1 Ω for this problem
   

   so RAB =	5	Ω
   	6

   
   

   Correct Option: A

   Suppose value of resistances be RΩ each. Applying KVL by selecting any path between A and B.
   

   VAB =	1	. R +	1	R +	1	R
   	3		6		3

   
   

   VAB = IR		5
   		6

   
   

   VAB	=	5R
   I		6

   
   

   or RAB =	5R
   	6

   
   where R = 1 Ω for this problem
   

   so RAB =	5	Ω
   	6

   
   

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