Architecture and Planning Miscellaneous-topic
- A five storied building is constructed on a 100 m × 50 m plot having ground coverage of 60% (option 1). Alternatively, a four storied building is constructed on the same plot with a 50% ground coverage (option 2). The ratio of FARs between options 1 and 2 is __________
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FAR = Total built up area Plot area
Total built up area in option 1 = (coverage area) × (no. of floors) = (100 × 50 × 0.6) × (5) = 15000
Total built up area in option 2 = (coverage area) × (no. of floors) = (100 × 50 × 0.5) × (4) = 10000
Plot area is common for both options = 100 × 50 = 5000m2So , FAR 1 = 1500 = 1.5 5000 FAR 2 10000 5000
Correct Option: B
FAR = Total built up area Plot area
Total built up area in option 1 = (coverage area) × (no. of floors) = (100 × 50 × 0.6) × (5) = 15000
Total built up area in option 2 = (coverage area) × (no. of floors) = (100 × 50 × 0.5) × (4) = 10000
Plot area is common for both options = 100 × 50 = 5000m2So , FAR 1 = 1500 = 1.5 5000 FAR 2 10000 5000
- If the annual net income from a commercial property is Rs 22,000/- and the interest rate is 8%, then the capitalized value in rupees of the property in perpetuity is _____________
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Let the value of the property is y
According to question, 8% of y is 22000y × 8 = 22000 100 8y = 22000 100
y = 275000Correct Option: A
Let the value of the property is y
According to question, 8% of y is 22000y × 8 = 22000 100 8y = 22000 100
y = 275000
- The actual roof area of a building is 3,60,000 sqm, which on a site plan measures 25 sqcm. The scale of the site plan is 1 : ______________
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Let the scale of the plan be 1 : Y .
So , 
1 
2 = 25 cm2 m2 = 1 × 10000 cm2 Y 360000 360000 = 1 = 1 2 12000 × 12000 12000 So , 1 = 1 Y 12000 Correct Option: A
Let the scale of the plan be 1 : Y .
So , 1 2 = 25 cm2 m2 = 1 × 10000 cm2 Y 360000 360000 = 1 = 1 2 12000 × 12000 12000 So , 1 = 1 Y 12000
- A hall is 15 m long and 12 m wide. If the sum of areas of the floor and ceiling is equal to the sum of the area of its four walls, then the volume of the hall in cubic meter is ______________
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Area of floor =15 × 12 = 180m2
Area of ceiling = 15 × 12 = 180 m2
Let the height of the wall be 'H' meter
According to the question,
Area of Floor + Area of ceiling = Area of four walls
So, 180 + 180 = wall perimeter × height of wall
So, 360 = [2(15 + 12)] × H
So, 360 = 54HSo , H = 20 meters 3
Therefore, volume of room = Length × Breadth × Height= 15 × 12 × 20 = 1200 m3 3 Correct Option: C
Area of floor =15 × 12 = 180m2
Area of ceiling = 15 × 12 = 180 m2
Let the height of the wall be 'H' meter
According to the question,
Area of Floor + Area of ceiling = Area of four walls
So, 180 + 180 = wall perimeter × height of wall
So, 360 = [2(15 + 12)] × H
So, 360 = 54HSo , H = 20 meters 3
Therefore, volume of room = Length × Breadth × Height= 15 × 12 × 20 = 1200 m3 3
- The housing stock of a town has total number of 9090 dwelling units. Present population of the town is 45,450. Assuming an aver age household size of 4.5, the housing shortage in percentage is _____________
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Present Population is 45,450
Household size is 4.5So, required no. of dwelling units 45450 = 10100 4.5
Current number of dwelling units = 9090
Shortage is: 10100 - 9090 = 10Correct Option: B
Present Population is 45,450
Household size is 4.5So, required no. of dwelling units 45450 = 10100 4.5
Current number of dwelling units = 9090
Shortage is: 10100 - 9090 = 10
