11. An industrial building contains 3000 kg of combustible materials, in dry state, distributed over three rooms of area 100 m², 500 m² and 300 m² each, in a proportion of 30%, 50% and 20% of the contents, respectively. Calorific value of the material is 4400 kCal/kg. The Total fire load of the rooms is equal to _______ kCal/m².

1. 1. 6160

   
   
   

   2. 22000

   
   
   

   3. 15400

   
   
   

   4. 61600

   
   
   

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1. View Hint View Answer Discuss in Forum

   Fire Load =	(Weight × Calorific Value)
   	Area

   
   

   Fire Load in Room 1 =	(300 × 0.3 × 4400)	= 39600 kCal / sq m
   	100

   
   

   Fire Load in Room 2 =	(300 × 0.5 × 4400)	= 13200 kCal / sq m
   	500

   
   

   Fire Load in Room 3 =	(300 × 0.2 × 4400)	= 8800 kCal / sq m
   	300

   
   Total Fire load = 39600 + 13200 + 8800 = 61600 kCal/sq m

   Correct Option: D

   Fire Load =	(Weight × Calorific Value)
   	Area

   
   

   Fire Load in Room 1 =	(300 × 0.3 × 4400)	= 39600 kCal / sq m
   	100

   
   

   Fire Load in Room 2 =	(300 × 0.5 × 4400)	= 13200 kCal / sq m
   	500

   
   

   Fire Load in Room 3 =	(300 × 0.2 × 4400)	= 8800 kCal / sq m
   	300

   
   Total Fire load = 39600 + 13200 + 8800 = 61600 kCal/sq m

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12. As per the Handbook on Barrier Free and Accessibility, CPWD – 2014, match the design guidelines in Column I with their appropriate standards in Column II and select the appropriate option.
    

    Column I	Column II
    P. Minimum clear width of ramp	1. 600 mm
    Q. Maximum height of wash basin (rim) above finished floor level	2. 1500 mm
    R. Minimum length of grab rail	3. 750 mm
    S. Minimum clear width for manoeuvring space (wheel chair)	4. 900 mm
    	5. 1800 mm

    
    

1. 1. P-3, Q-4, R-1, S-5

   
   
   

   2. P-5, Q-3, R-2, S-4

   
   
   

   3. P-5, Q-3, R-1, S-2

   
   
   

   4. P-1, Q-4, R-3, S-1

   
   
   

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1. View Hint View Answer Discuss in Forum

   Refer the Handbook on Barrier Free and Accessibility, CPWD – 2014.

   Correct Option: C

   Refer the Handbook on Barrier Free and Accessibility, CPWD – 2014.

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13. Match the thermal properties in the column I and their respective units in Column II and select the appropriate option.
    

    Column I	Column II
    P. Thermal resistance	1. J kg– 1°C– 1
    Q. Thermal Transmittance	2. Wm– 1 °C– 1
    R. Specific heat	3. Wm– 2°C– 1
    S. Thermal Conductivity	4. m2°CW– 1
    	5. J m– 3°C– 1

    
    

1. 1. P-4, Q-1, R-5, S-2

   
   
   

   2. P-4, Q-3, R-1, S-2

   
   
   

   3. P-5, Q-3, R-1, S-4

   
   
   

   4. P-3, Q-4, R-2, S-1

   
   
   

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1. View Hint View Answer Discuss in Forum

   NA

   Correct Option: B

   NA

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14. For a symmetrical trapezoidal open drain in a landscape with grass and loose rock, surface, the velocity of flow of water is ___ m/sec, (round off to two decimal places), given the following data.
    Water edge width at the top = 750 mm
    Water edge width at the bottom = 45000 mm
    Water depth = 600 mm
    Manning’s coefficient of roughness = 0.05
    Slope along the drain = 1 in 250

1. 1. 4.5

   
   
   

   2. 0.45

   
   
   

   3. 45

   
   
   

   4. 1.5

   
   
   

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1. View Hint View Answer Discuss in Forum

   Velocity of water (in m/sec) =	1	× r2 / 3 × S1 / 2
   	n

   
   Here, n = 0.05
   

   Hydraulic radius , r =	Wet area
   	Wet perimeter

   
   

   =	0.36	= 0.2134
   	1.6869

   
   

   S =	1	= 0.004 m
   	250

   
   

   Velocity =	1	× (0.2134)2 / 3 × (0.004)1 / 2 = 0.45 m / sec
   	0.05

   Correct Option: B

   Velocity of water (in m/sec) =	1	× r2 / 3 × S1 / 2
   	n

   
   Here, n = 0.05
   

   Hydraulic radius , r =	Wet area
   	Wet perimeter

   
   

   =	0.36	= 0.2134
   	1.6869

   
   

   S =	1	= 0.004 m
   	250

   
   

   Velocity =	1	× (0.2134)2 / 3 × (0.004)1 / 2 = 0.45 m / sec
   	0.05

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15. A simply supported beam AB has a clear span of 7 meter. The bending moment diagram (BMD) of the beam due to a single concentrated load is shown in the figure below.
    
    The magnitude of the concentrated load in kN is _________.
    

1. 1. 12

   
   
   

   2. 7

   
   
   

   3. 21

   
   
   

   4. 42

   
   
   

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1. View Hint View Answer Discuss in Forum

   For eccentric point load on a simply supported beam
   
   Moment along any plane xx’,
   M_X = R_A x = Wbx / L
   M_X = Wbx / L
   Maximum Bending Moment
   

   =	Wab	=	(W × 3 × 4)
   	L		7

   
   

   36 =	12W
   	7

   
   

   W =	(36 × 7)	= 21
   	12

   
   

   Correct Option: C

   For eccentric point load on a simply supported beam
   
   Moment along any plane xx’,
   M_X = R_A x = Wbx / L
   M_X = Wbx / L
   Maximum Bending Moment
   

   =	Wab	=	(W × 3 × 4)
   	L		7

   
   

   36 =	12W
   	7

   
   

   W =	(36 × 7)	= 21
   	12

   
   

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