Architecture and Planning Miscellaneous-topic

Architecture and Planning Miscellaneous-topic

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Architecture and Planning Miscellaneous

Architecture and Planning Miscellaneous-topic
  1. Area of tensile steel per meter width of a reinforced concrete slab is 335 sq mm. If 8 mm rods are used as reinforcement, then centre to centre spacing of the reinforcement in mm is ________








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    Total area of steel is 335 mm2
    Area of 8 mm rod = π r 2 = 3.14 × 4 × 4 = 50.24 mm2

    Total no. of rods spread in 1m of width =
    335
    		= 6.67
    50.24

    So, 7 rods are spread in 1 m of width.
    So, distance between two rods will be 1m / 6.67 = 150 mm

    Correct Option: B

    Total area of steel is 335 mm2
    Area of 8 mm rod = π r 2 = 3.14 × 4 × 4 = 50.24 mm2

    Total no. of rods spread in 1m of width =
    335
    		= 6.67
    50.24

    So, 7 rods are spread in 1 m of width.
    So, distance between two rods will be 1m / 6.67 = 150 mm

  1. A class room measuring 10 m (L) × 8 m (B) × 2.7 m (H) requires an illumination level of 500 lux on the desk level using 40 W fluorescent lamps with rated output of 5000 lumens each. Assuming utilization factor of 0.5 and maintenance factor of 0.8, the number of lamps required is _________








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    500 lux = 500 lumen/m2
    Total lumen required = (500 lumen/m2) × (Area of the room) = 500 × 10 × 8
    Lumen output of one lamp = 5000 lumen (given)
    Actually the lumen output of the lamp will be less than 5000 lumen because of utilization factor and maintenance factor. So, net lumen output = 5000 × 0.5 × 0.8

    Required no. of lamps =
    Total lumen required
    		=
    500 × 10 × 8
    		 = 20
    lumen of on lamp5000 × 0.5 × 0.8

    Correct Option: A

    500 lux = 500 lumen/m2
    Total lumen required = (500 lumen/m2) × (Area of the room) = 500 × 10 × 8
    Lumen output of one lamp = 5000 lumen (given)
    Actually the lumen output of the lamp will be less than 5000 lumen because of utilization factor and maintenance factor. So, net lumen output = 5000 × 0.5 × 0.8

    Required no. of lamps =
    Total lumen required
    		=
    500 × 10 × 8
    		 = 20
    lumen of on lamp5000 × 0.5 × 0.8

  1. The number of standard cement bags required to prepare 1400 kg of concrete in the ratio of 1 : 2 : 4 (mixed by weight batching) is___________








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    1 : 2 : 4 → 1part cement : 2 part sand : 4 part aggregates
    So, To make 7 kg of concrete, amount of cement required = 1 kg

    So, To make 1 kg of concrete, amount of cement required =
    1
    		 kg
    7

    So, To make 1400 kg of concrete, amount of cement required =
    1
    		 × 1400 = 200 kg
    7

    1 bag of cement contains 50 kg of cement
    Number of bags required =
    200 kg
    		 = 4 bags
    50 kg

    Correct Option: D

    1 : 2 : 4 → 1part cement : 2 part sand : 4 part aggregates
    So, To make 7 kg of concrete, amount of cement required = 1 kg

    So, To make 1 kg of concrete, amount of cement required =
    1
    		 kg
    7

    So, To make 1400 kg of concrete, amount of cement required =
    1
    		 × 1400 = 200 kg
    7

    1 bag of cement contains 50 kg of cement
    Number of bags required =
    200 kg
    		 = 4 bags
    50 kg

  1. A landscaped garden with irregular profile and minor undulations, measuring 35,000 sqm, has a total surface area covered with 20% brick paving, 15% cement concrete paving, and rest with grass. The peak intensity of rainfall in that region is 70 mm/hr. The coefficient of runoff for brick paving, cement concrete paving and grass is 0.8, 0.9 and 0.5 respectively. The estimated quantity of runoff in cubic meter/hr for the entire garden area is _____________








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    Brick paving area = 20% of 35000 = 7000 m2
    Concrete paving area = 15% of 35000 = 5250 m2
    Grass cover area = 65% of 35000 = 22750 m2
    Water runoff by brick paving = 0.8 × 7000 m2 area × 0.07 m of rain fall = 392.0 m3
    Water runoff by concrete paving = 0.9 ×5250 m2 area x 0.07 m of rain fall = 330.75 m3
    Water runoff by grass cover = 0.5 × 22750 m2 area × 0.07 m of rain fall = 796.25 m3

    Correct Option: B

    Brick paving area = 20% of 35000 = 7000 m2
    Concrete paving area = 15% of 35000 = 5250 m2
    Grass cover area = 65% of 35000 = 22750 m2
    Water runoff by brick paving = 0.8 × 7000 m2 area × 0.07 m of rain fall = 392.0 m3
    Water runoff by concrete paving = 0.9 ×5250 m2 area x 0.07 m of rain fall = 330.75 m3
    Water runoff by grass cover = 0.5 × 22750 m2 area × 0.07 m of rain fall = 796.25 m3

  1. A simply supported beam having effective span of 5 meter is carrying a centrally concentrated load of 16 kN. The maximum bending moment in the beam in kN-m is ________








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    Maximum bending moment will at center =
    PL
    		 = 20
    4

    Correct Option: D

    Maximum bending moment will at center =
    PL
    		 = 20
    4