Architecture and Planning Miscellaneous-topic


Architecture and Planning Miscellaneous-topic

Architecture and Planning Miscellaneous

  1. The internal dimension of a room is 10m × 10m × 4m (height). The total area of the doors and windows are 16 m2. Keeping the doors and windows closed, the reverberation time of the room becomes 1.2 second. Assume all the interior surfaces including doors and windows have some absorption coefficient. If all doors and windows of the room are kept fully open, the reverberation time will be _____ second (rounded of to one decimal place).









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    Consider the uniform absorption coefficient = a

    Now, RT (Reverberation Time) = Constant ×
    Volume
    Absorption

    Constant = 0.16 (in metric system)
    1.2 = 0.16 ×
    400
    360a

    Since, Total surface area of room is 360
    360a = 400 ×
    0.16
    1.2

    a = 0.148
    If all the doors and windows of the room are kept open,
    New RT = 0.16 ×
    400
    344a

    Since, Surface Area = Total Surface Area – Area under Doors & Windows = 360 – 16
    RT =
    (0.16 × 400)
    = 1.26 seconds
    (344 × 0.148)

    Correct Option: B

    Consider the uniform absorption coefficient = a

    Now, RT (Reverberation Time) = Constant ×
    Volume
    Absorption

    Constant = 0.16 (in metric system)
    1.2 = 0.16 ×
    400
    360a

    Since, Total surface area of room is 360
    360a = 400 ×
    0.16
    1.2

    a = 0.148
    If all the doors and windows of the room are kept open,
    New RT = 0.16 ×
    400
    344a

    Since, Surface Area = Total Surface Area – Area under Doors & Windows = 360 – 16
    RT =
    (0.16 × 400)
    = 1.26 seconds
    (344 × 0.148)


  1. A power shovel is having 1.8 m2 excavation output per batch of operation. The average cycle time of the batch operation is 45 seconds. The lost time per hour of the excavation activity is 10 minutes. Assume six working hours of operation per day. The amount of soil excavated by the power shovel per day is ________ m3 (rounded of to one decimal place).









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    Considering 10 min loss per hour,
    Effective operating time per day = 50 × 6 = 300 min

    Volume of soil excavated =
    (300 × 60 × 1.8)
    = 720 cum
    45

    Correct Option: A

    Considering 10 min loss per hour,
    Effective operating time per day = 50 × 6 = 300 min

    Volume of soil excavated =
    (300 × 60 × 1.8)
    = 720 cum
    45



  1. A cone, with a base of 10 cm diameter and axis of 12 cm, is lying on Horizontal Plane (HP) along its generator. The internal angle which is the base of the cone makes with HP is _____ degrees.









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    tan θ =
    height
    =
    12
    base5

    θ = 67.6 °
    Alternatively, using Pythogorean theorem, hypotenuse i.e. the length of the cone is calculated to be 13 cm.

    cos θ =
    base
    =
    5
    hypotaneous13

    cos θ = 0.38
    θ = 67.6 °

    Correct Option: C

    tan θ =
    height
    =
    12
    base5

    θ = 67.6 °
    Alternatively, using Pythogorean theorem, hypotenuse i.e. the length of the cone is calculated to be 13 cm.

    cos θ =
    base
    =
    5
    hypotaneous13

    cos θ = 0.38
    θ = 67.6 °


  1. Match the scientific names of the trees provided in Column I with the corresponding colour of their bloom in Column II, and select the appropriate option.
    Column I Column II
    P. Cassia fistula 1. White
    Q. Lagerstroemia 2. Red flos-reginae
    R. Cordia sebastena 3. Blue
    S. Plumeria alba 4. Yellow
    5. Mauve









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    Correct Option: D



  1. Match the figures of vault in Column I with their corresponding types in column II and select the appropriate option.










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    Barrel Vault is the simplest of the vaults and is the base design for many vaults that have a more intricate design. It consists of an ongoing series of semicircular arches. One is directly behind another, causing it to look like a half of a barrel. In some instances, it is described as resembling a tunnel. Groin Vault is created by two barrel vaults intersecting at right angles. The arches of groin vaults are round or point ed. It is also known as a cross vault. Rib Vault is a vault reinforced by masonry ribs is known as a rib vault. When this type of vault has two masonry ribs dividing it i nt o four sect i ons, i t is cal led a quadripartite rib vault. A vault divided by three masonry ribs that make six sections is called a sexpartite rib vault. Half cones that are fanshaped are know as Fan vaults. The cones meet in the center of the vault. This vault is considered to be a part of the rib vault family. Nubian vault is a type of curved surface forming a vaulted structure. The mudbrick structure was revived by Egyptian architect Hassan Fathy after rediscovering the technique in the Nubian village of Abual-Riche.

    Correct Option: A

    Barrel Vault is the simplest of the vaults and is the base design for many vaults that have a more intricate design. It consists of an ongoing series of semicircular arches. One is directly behind another, causing it to look like a half of a barrel. In some instances, it is described as resembling a tunnel. Groin Vault is created by two barrel vaults intersecting at right angles. The arches of groin vaults are round or point ed. It is also known as a cross vault. Rib Vault is a vault reinforced by masonry ribs is known as a rib vault. When this type of vault has two masonry ribs dividing it i nt o four sect i ons, i t is cal led a quadripartite rib vault. A vault divided by three masonry ribs that make six sections is called a sexpartite rib vault. Half cones that are fanshaped are know as Fan vaults. The cones meet in the center of the vault. This vault is considered to be a part of the rib vault family. Nubian vault is a type of curved surface forming a vaulted structure. The mudbrick structure was revived by Egyptian architect Hassan Fathy after rediscovering the technique in the Nubian village of Abual-Riche.