Architecture and Planning Miscellaneous-topic
Direction: A cantilever beam XY of 2.5 m span is supported at P and is subjected to 40 kN point load at free end Y.
- If self-weight of the beam is neglected, bending moment developed at the fixed end (in kN-m) is
-
View Hint View Answer Discuss in Forum
B. M at P = 40 × 2.5 = 100 KN – mCorrect Option: B
B. M at P = 40 × 2.5 = 100 KN – m
Direction: An office has an area of 60 sq.m with floor height of 3 m and occupancy of 5 persons. The external wall area is 40 sq.m which includes 4 sq.m of double glazed windows. The thermal trans-mittance rate (U) of external wall is 0.35 and window is 2.00. External and internal design temperatures are 34°C and 22°C respectively.
- If 20 lit/sec/person of air is extracted from the office, the ventilation rate in terms of air changes/ hour is_____
-
View Hint View Answer Discuss in Forum
The fresh air supply to a room can be calculated as, q = n V
Where, q = fresh air supply (ft 3 /h, m3 /h)
n = air change rate (h–1)
V = volume of room (ft³, m³)
Ventilation rate in terms of N number of air changes per hour and the room volume is given by the formula:
V = N × room volume/ 3600 (3600 is the number of seconds in an hour)
Here, V = total number of people × ventilation rate in m³/sec/person.
20 × 5 × 0.001 = N × 60 × (3/3600) N = 2.0Correct Option: A
The fresh air supply to a room can be calculated as, q = n V
Where, q = fresh air supply (ft 3 /h, m3 /h)
n = air change rate (h–1)
V = volume of room (ft³, m³)
Ventilation rate in terms of N number of air changes per hour and the room volume is given by the formula:
V = N × room volume/ 3600 (3600 is the number of seconds in an hour)
Here, V = total number of people × ventilation rate in m³/sec/person.
20 × 5 × 0.001 = N × 60 × (3/3600) N = 2.0
- The heat gain through the external walls and windows (in watts) will be______
-
View Hint View Answer Discuss in Forum
To calculate the amount of heat transfer, Φ = A × U × (T1 – T2)
Where Φ is the heat transfer in watts, U is the thermal transmittance, T1 is the temperature on one side of the structure, T2 is the temperature on the other side of the structure and A is the area in square metres.
Φ = 36 × 0.35 × (34 – 22) + 4 × 2.0 × (34 – 22)
= 151.2 + 96 = 247.2 wattsCorrect Option: A
To calculate the amount of heat transfer, Φ = A × U × (T1 – T2)
Where Φ is the heat transfer in watts, U is the thermal transmittance, T1 is the temperature on one side of the structure, T2 is the temperature on the other side of the structure and A is the area in square metres.
Φ = 36 × 0.35 × (34 – 22) + 4 × 2.0 × (34 – 22)
= 151.2 + 96 = 247.2 watts
Direction: A seminar hall has a volume of 2000 cu.m, and the total absorption of all acoustic materials without any audience is 80 m² -sabines.
- When the same seminar hall is filled with audience, the reverberation time is recorded as 2.0 seconds. Then the total absorption of all acoustic materials (in m² -sabines) will be
-
View Hint View Answer Discuss in Forum
t = 0.161V Sa 2 = 0.161 × 2000 Sa
Sa = 160 m² – sabinesCorrect Option: C
t = 0.161V Sa 2 = 0.161 × 2000 Sa
Sa = 160 m² – sabines
- The reverberation time of the empty hall (in seconds) will be
-
View Hint View Answer Discuss in Forum
t = 0.161V Sa t = 0.161 × 2000 80
= 4 seconds.Correct Option: B
t = 0.161V Sa t = 0.161 × 2000 80
= 4 seconds.
