Direction: A seminar hall has a volume of 2000 cu.m, and the total absorption of all acoustic materials without any audience is 80 m² -sabines.
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When the same seminar hall is filled with audience, the reverberation time is recorded as 2.0 seconds. Then the total absorption of all acoustic materials (in m² -sabines) will be
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- 40
- 80
- 160
- 320
Correct Option: C
| t = | ||
| Sa |
| 2 = | ||
| Sa |
Sa = 160 m² – sabines
