Architecture and Planning Miscellaneous-topic


Architecture and Planning Miscellaneous-topic

Architecture and Planning Miscellaneous

  1. As per the CPWD Handbook on Barrier Free and Accessibility, 2014, Government of I ndia, the minimum length of a straight ramp in metre to raise a wheelchair to the plinth level of 600 mm, is ___________









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    As per CPWD handbook on Barrier Free and Accessibility 2014, maximum gradient of ramp should be 1 : 12. It means to raise a height of 1 m (1000 mm), it requires 12 m (12000 mm) length of ramp.
    Thus, to raise a wheelchair to height 600 mm, it requires 12 × 600 = 7200 mm = 7.2 m ramp

    Correct Option: A

    As per CPWD handbook on Barrier Free and Accessibility 2014, maximum gradient of ramp should be 1 : 12. It means to raise a height of 1 m (1000 mm), it requires 12 m (12000 mm) length of ramp.
    Thus, to raise a wheelchair to height 600 mm, it requires 12 × 600 = 7200 mm = 7.2 m ramp


  1. The concepts of ‘serial vision’, ‘punctuation’ and ‘closure’ were proposed by









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    Serial vision :
    Gordon Cullen (1961) conceived the concept of "serial vision' He said :
    Urban experience is one of a series of revelations, with delight and interest being stimulated by contrasts.

    Correct Option: C

    Serial vision :
    Gordon Cullen (1961) conceived the concept of "serial vision' He said :
    Urban experience is one of a series of revelations, with delight and interest being stimulated by contrasts.



  1. In one litre of paint, volume of solid pigment and volume of non-volatile binder are 400 cc and 600 cc respectively. The Pigment Volume Concentration number of the paint is __________









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    cc stands for cubic centimeters, a unit of volume. So, 1000 cc means 1 liters.
    Here, pigment volume concentration

    =
    400
    × 100 = 40
    1000

    Correct Option: B

    cc stands for cubic centimeters, a unit of volume. So, 1000 cc means 1 liters.
    Here, pigment volume concentration

    =
    400
    × 100 = 40
    1000


  1. The internal dimension of a room is 10m × 10m × 4m (height). The total area of the doors and windows are 16 m2. Keeping the doors and windows closed, the reverberation time of the room becomes 1.2 second. Assume all the interior surfaces including doors and windows have some absorption coefficient. If all doors and windows of the room are kept fully open, the reverberation time will be _____ second (rounded of to one decimal place).









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    Consider the uniform absorption coefficient = a

    Now, RT (Reverberation Time) = Constant ×
    Volume
    Absorption

    Constant = 0.16 (in metric system)
    1.2 = 0.16 ×
    400
    360a

    Since, Total surface area of room is 360
    360a = 400 ×
    0.16
    1.2

    a = 0.148
    If all the doors and windows of the room are kept open,
    New RT = 0.16 ×
    400
    344a

    Since, Surface Area = Total Surface Area – Area under Doors & Windows = 360 – 16
    RT =
    (0.16 × 400)
    = 1.26 seconds
    (344 × 0.148)

    Correct Option: B

    Consider the uniform absorption coefficient = a

    Now, RT (Reverberation Time) = Constant ×
    Volume
    Absorption

    Constant = 0.16 (in metric system)
    1.2 = 0.16 ×
    400
    360a

    Since, Total surface area of room is 360
    360a = 400 ×
    0.16
    1.2

    a = 0.148
    If all the doors and windows of the room are kept open,
    New RT = 0.16 ×
    400
    344a

    Since, Surface Area = Total Surface Area – Area under Doors & Windows = 360 – 16
    RT =
    (0.16 × 400)
    = 1.26 seconds
    (344 × 0.148)



  1. A pointed arch having two centres and radii greater than the span is known as









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    Correct Option: A