Architecture and Planning Miscellaneous-topic
- In a site map, a rectangular residential plot measures 150 mm × 40 mm, and the depth of the front road in the map measures 16 mm. Actual width of the road is 4m. If the permissible F.A.R is 1.2, the maximum built up area for the residential building will be _____ m2 .
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The map is scaled 4000 times i.e 250 times, as inferred from 16
the dimensions of the road. Thus the actual area of plot = (0.15 × 250) × (0.04 × 250) sq m = 37.5 × 10 = 375 sq m
Since, the Permissible F.A .R. i s 1.2, the maximum built -up area for the residential building is 1.2 × 375 sq m = 450 sq m
Correct Option: B
The map is scaled 4000 times i.e 250 times, as inferred from 16
the dimensions of the road. Thus the actual area of plot = (0.15 × 250) × (0.04 × 250) sq m = 37.5 × 10 = 375 sq m
Since, the Permissible F.A .R. i s 1.2, the maximum built -up area for the residential building is 1.2 × 375 sq m = 450 sq m
- Match the Name of book provided in Column I with the corresponding author in Column II and select the appropriate option.
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NA
Correct Option: A
NA
- A public utility building of 5000 m2 was constructed 5 years before, on a site of 1 hectare. The present value of open land in that location is Rs. 100/m2 and present construction cost of such building is Rs. 2500/m2. If the value of the building is assumed to be depreciating at a constant rate of 6 percent per annum, then the present value of the property using ‘Valuatin by Cost Method’ is ______ (in Rs. Lakh) (rounded off to one decimal place).
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Present Land value = Rs. 100 × 10,000 = Rs. 10 lakhs
Cost of Construction of the building = Total Area × Per Sq m
Cost of Construction = 5,000 × 2500 = 125 lakhs
Depreciation rate = 6% Value of the building after depreciation in 5 years = 125 (1 – r)n = 125 × (1 – 0.06)5 = 91.7 lakhs
Present Value of Property = Land Value + Building Value = 10+ 91.7 = 101.7 lakhsCorrect Option: C
Present Land value = Rs. 100 × 10,000 = Rs. 10 lakhs
Cost of Construction of the building = Total Area × Per Sq m
Cost of Construction = 5,000 × 2500 = 125 lakhs
Depreciation rate = 6% Value of the building after depreciation in 5 years = 125 (1 – r)n = 125 × (1 – 0.06)5 = 91.7 lakhs
Present Value of Property = Land Value + Building Value = 10+ 91.7 = 101.7 lakhs
- A depressed portion of a land is identified by three closed contours, as shown in the figure below. The area bound by three contour lines is 6 m2, 24 m2 and 96 m2 respectively.
The contour interval is 1 m. Using prismoidal method, the volume of the earth needed to fill land depression is ________m3 .
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The volume of a prismoid is :
V = - 1 (A1 + 4Am + A2) 6
Where: V = Volume (cubic feet) Am = Middle Area or Area of a plane surface midway between A1 and A2, A1 and A2 are the areas of the end sections. L is distance between top and bottom cross-section.V = 
3 
× {[96 + (4 × 24) + 6]} = 198 = 99 cu m 6 2
Correct Option: B
The volume of a prismoid is :
V = - 1 (A1 + 4Am + A2) 6
Where: V = Volume (cubic feet) Am = Middle Area or Area of a plane surface midway between A1 and A2, A1 and A2 are the areas of the end sections. L is distance between top and bottom cross-section.V = 3 × {[96 + (4 × 24) + 6]} = 198 = 99 cu m 6 2
- Match the following in Column I with t heir suitable description in Column II, and select the appropriate option.
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NA
Correct Option: D
NA
