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For a symmetrical trapezoidal open drain in a landscape with grass and loose rock, surface, the velocity of flow of water is ___ m/sec, (round off to two decimal places), given the following data.
Water edge width at the top = 750 mm
Water edge width at the bottom = 45000 mm
Water depth = 600 mm
Manning’s coefficient of roughness = 0.05
Slope along the drain = 1 in 250
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- 4.5
- 0.45
- 45
- 1.5
Correct Option: B
Velocity of water (in m/sec) = | × r2 / 3 × S1 / 2 | |
n |
Here, n = 0.05
Hydraulic radius , r = | ||
Wet perimeter |
= | = 0.2134 | |
1.6869 |
S = | = 0.004 m | |
250 |
Velocity = | × (0.2134)2 / 3 × (0.004)1 / 2 = 0.45 m / sec | |
0.05 |