Discount
 The marked price of watch was ₹ 820. A man bought the watch for ₹ 570.72 after getting two successive discounts, of which the first was 20%. The second discount was

 18%
 15%
 13%
 11%

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Total discount = ₹ (820 – 570.72) = ₹ 249.28
First discount = 820 × 20 = ₹ 164 100
∴ Second discount = ₹ (249.28 – 164) = ₹ 85.28
Price of the article after first discount = ₹ (820 – 164) = ₹ 656
If the second discount be D_{2} % ,
then D_{2} % of 656 = 85.28
Alternate method to solve this question :
Here, M.P. = Rs. 820, S.P. = 570.72, D_{1} = 20%, D_{2} = ?S.P. = M.P. 100 − D_{1} 100 − D_{2} 100 100 Correct Option: C
Total discount = ₹ (820 – 570.72) = ₹ 249.28
First discount = 820 × 20 = ₹ 164 100
∴ Second discount = ₹ (249.28 – 164) = ₹ 85.28
Price of the article after first discount = ₹ (820 – 164) = ₹ 656
If the second discount be D_{2} % ,
then D_{2} % of 656 = 85.28⇒ D_{2} = 85.28 × 100 = 13% 656
Alternate method to solve this question :
Here, M.P. = Rs. 820, S.P. = 570.72, D_{1} = 20%, D_{2} = ?S.P. = M.P. 100 − D_{1} 100 − D_{2} 100 100 570.72 = 820 100 − 20 100 − D_{2} 100 100 5707200 = 100 − D_{2} 820 × 80
100 − D_{2} = 87
D_{2} = 13 %
 An article is listed at ₹ 920. A customer pays ₹ 742.90 for it after getting two successive discounts. If the rate of first discount is 15%, the rate of 2nd discount is

 3%
 5%
 8%
 12%

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Total discount = ₹ (920 – 742.90) = ₹ 177.10
First discount = 15%
∴ Discount = 15% of 920= 920 × 15 = ₹ 138 100
Price after this discount = 920 – 138 = ₹ 782
Remaining discount = 177.10 – 138 = ₹ 39.10
Let the second discount be D_{2} %.∴ 782 × D_{2} = 39.10 100
Alternate method to solve this question :
Here, M.P. = Rs. 920, S.P. = Rs. 742.90
D_{1} = 15%, D_{2} = ?S.P. = M.P. 100 − D_{1} 100 − D_{2} 100 100 742.90 = 920 100 − 15 100 − D_{2} 100 100
Correct Option: B
Total discount = ₹ (920 – 742.90) = ₹ 177.10
First discount = 15%
∴ Discount = 15% of 920= 920 × 15 = ₹ 138 100
Price after this discount = 920 – 138 = ₹ 782
Remaining discount = 177.10 – 138 = ₹ 39.10
Let the second discount be D_{2} %.∴ 782 × D_{2} = 39.10 100 ⇒ D_{2} = 39.10 × 100 = 5% 782
Alternate method to solve this question :
Here, M.P. = Rs. 920, S.P. = Rs. 742.90
D_{1} = 15%, D_{2} = ?S.P. = M.P. 100 − D_{1} 100 − D_{2} 100 100 742.90 = 920 100 − 15 100 − D_{2} 100 100 7429000 = 100 − D_{2} 920 × 85
95 = 100 – D_{2}
⇒ D_{2} = 5%
 The difference between a discount of 40% on ₹ 500 and two successive discounts of 36 % and 4 % on the same amount is

 zero
 ₹ 1.93
 ₹ 2.00
 ₹ 7.20

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As we know the formula for a equivalent discount for two success discounts.
Single equivalent discount of two successive discounts of 36% and 4%.= 36 + 4 − 36 × 4 100
= 40 – 1.44 = 38.56
Percentage difference = 40 – 38.56 = 1.44
Correct Option: D
As we know the formula for a equivalent discount for two success discounts.
Single equivalent discount of two successive discounts of 36% and 4%.= 36 + 4 − 36 × 4 100
= 40 – 1.44 = 38.56
Percentage difference = 40 – 38.56 = 1.44∴ Required difference = 500 × 1.44 = ₹ 7.20 100
 An article is listed at ₹ 900 and two successive discounts of 8% and 8% are given on it. How much would the seller gain or lose, if he gives a single discount of 16%, instead of two discounts ?

 Gain of ₹ 4.76
 Loss of ₹ 5.76
 Gain of ₹ 5.76
 Loss of ₹ 4.76

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As we know the formula for a equivalent discount for two successive discount.
Equivalent discount for two successive discounts of 8% and 8%= 8 + 8 − 8 × 8 % 100
For a single discount of 16%,
SP = 84 % of 900
Correct Option: B
As we know the formula for a equivalent discount for two successive discount.
Equivalent discount for two successive discounts of 8% and 8%= 8 + 8 − 8 × 8 % 100
= (16–0.64) % = 15.36 %
∴ SP = (100 –15.36) % of 900= ₹ 84.64 × 900 = ₹ 761.76 100
For a single discount of 16%,
SP = 84% of 900= ₹ 84 × 900 = ₹ 756 100
Certainly seller will lose in this case.
∴ Loss = ₹ (761.76 – 756)
= ₹ 5.76
 The list price of a clock is ₹ 160. A customer buys it for ₹ 122.40 after two successive discounts. If first discount is 10%, the second is

 10%
 12%
 15%
 18%

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As per given question marked price = 160
After 10% discount, The Selling priceS.P. = 100  10 × 160 = ₹ 144 100
Let us assume the other discount = D%∴ (100 − D) × 144 = ₹ 122.40 100 ⇒ 100 − D = 12240 144
Alternate method to solve this question :S.P. = M.P. 100 − D_{1} 100 − D_{2} 100 100 Correct Option: C
As per given question marked price = 160
After 10% discount, The Selling priceS.P. = 100  10 × 160 = ₹ 144 100
Let us assume the other discount = D%∴ (100 − D) × 144 = ₹ 122.40 100 ⇒ 100 − D = 12240 144
⇒ 100 – D = 85
⇒ D = 100 – 85 = 15%
Alternate method to solve this question :S.P. = M.P. 100 − D_{1} 100 − D_{2} 100 100 ⇒ 122.40 = 160 100 − 10 100 − D_{2} 100 100 12240 = 90 × 100  D_{2} 160 100 1224000 = 100 − D_{2} 160 × 90 12240 = 100 − D_{2} 16 × 9 1360 = 100 − D_{2} 16 × 1
⇒ 85 = 100 – D_{2}
⇒ D_{2} = 15%