Discount
 A scooter is sold at three successive discounts of 10%, 5% and 2%. If the marked price of the scooter is Rs. 18,000, find its net selling price.

 Rs. 15028.20
 Rs. 15082.00
 Rs. 15082.20
 Rs. 15080.00

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According to given question.
Here, D_{1} = 10%, D_{2} = 5%, D_{3} = 2%
Net Selling Price of Sccoter= Marked Price x 100 − D_{1} 100 − D_{2} 100 − D_{3} 100 100 100
Correct Option: C
According to given question.
Here, D_{1} = 10%, D_{2} = 5%, D_{3} = 2%
Net Selling Price of Sccoter= Marked Price x 100 − D_{1} 100 − D_{2} 100 − D_{3} 100 100 100
Net selling price of scooter.= Rs. 18000 × 90 × 95 × 98 100 100 100
= Rs. 15082.2
 The difference between successive discounts of 40% followed by 30% and 45% followed by 20% on the marked price of an article is Rs. 12. The marked price of the article is :

 ₹ 800
 ₹ 400
 ₹ 200
 ₹ 600

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Single equivalent discount for 40% and 30%
= 40 + 30 − 40 × 30 % 100
= (70 – 12)% = 58%
Single equivalent discount for 45% and 20%= 45 + 20 − 45 × 20 % 100
= (65 – 9)% = 56%
Let the marked price be Rs. M.
According to the question,
M × (58 – 56)% = 12
Correct Option: D
Single equivalent discount for 40% and 30%
= 40 + 30 − 40 × 30 % 100
= (70 – 12)% = 58%
Single equivalent discount for 45% and 20%= 45 + 20 − 45 × 20 % 100
= (65 – 9)% = 56%
Let the marked price be Rs. M.
According to the question,
M × (58 – 56)% = 12⇒ M × 2 = 12 100 ⇒ M = 1200 = Rs. 600 2
 A double bed is marked at ₹ 7,500. The shopkeeper allows successive discounts of 8%, 5% and 2% on it. What is the net selling price ?

 ₹ 6, 500
 ₹ 6,000
 ₹ 6,423.90
 ₹ 6,500.50

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As we know the formula for two successive discount.
Single equivalent discount = D_{1} + D_{2} − D_{1} × D_{2} % 100 Single equivalent discount for 8% and 5% = 8 + 5 − 8 × 5 % 100
Single equivalent discount for 8% and 5% = (13 – 0.4) = 12.6 %
Similarly calculate other discount and Solve the question for Net Selling price of product.
Alternate method to solve this question :
According to given question.
M.P. = ₹ 7500, S.P. = ?, D_{1} = 8%, D_{2} = 5%, D_{3} = 2%S.P = M.P. 100 − D_{1} 100 − D_{2} 100 − D_{3} 100 100 100 S.P = 7500 100 − 8 100 − 5 100 − 2 100 100 100 Correct Option: C
As we know the formula for two successive discount.
Single equivalent discount = D_{1} + D_{2} − D_{1} × D_{2} % 100 Single equivalent discount for 8% and 5% = 8 + 5 − 8 × 5 % 100 Single equivalent discount for 8% and 5% = 8 + 5 − 8 × 5 % 100
Single equivalent discount for 8% and 5% = (13 – 0.4) = 12.6 %Single equivalent disconut for 12.6% and 2% = 12.6 + 2 − 12.6 × 2 % 100
Single equivalent disconut for 12.6% and 2% = 14.6 – 0.252 = 14.348 %
∴ Net S.P = (100 – 14.348) % of 7500∴ Net S.P = 7500 × 85.652 = ₹ 6423.90 100
Alternate method to solve this question :
According to given question.
M.P. = ₹ 7500, S.P = ?, D_{1} = 8%, D_{2} = 5%, D_{3} = 2%S.P = M.P. 100 − D_{1} 100 − D_{2} 100 − D_{3} 100 100 100 S.P = 7500 100 − 8 100 − 5 100 − 2 100 100 100 S.P = 7500 × 92 × 95 × 98 100 100 100
S.P = ₹ 6423.90
 A plate was sold for 6,300 after giving two successive discounts of
12 1 % and 10%. Find the marked price. 2

 ₹ 7,300
 ₹ 7,700
 ₹ 8,000
 ₹ 7,250

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Single equivalent discount for two successive discounts
= x + y − xy % 100 = 25 + 10 − 25 × 10 % 2 100
= ( 12.5 + 10 – 1.25 )%
= 21.25 %
If the marked price of the plate be ₹ M and solve this question further.
Alternate method to solve this question :
According to given question.
Here, S.P. = 6300, M.P. = ?
D_{1} = 25/2 %, D_{2} = 10%S.P. = M.P. 100 − D_{1} 100 − D_{2} 100 100 6300 = M.P. 100 − 25/2 100 − 10 100 100 ⇒ 6300 = M.P. 175 90 200 100
Correct Option: C
Single equivalent discount for two successive discounts
= x + y − xy % 100 = 25 + 10 − 25 × 10 % 2 100
= ( 12.5 + 10 – 1.25 )%
= 21.25 %
If the marked price of the plate be ₹ M, then
= (100 – 21.25 ) % of M = 6300⇒ M × 78.75 = 6300 100 ⇒ M = 6300 × 100 = ₹ 8000 78.75
Alternate method to solve this question :
According to given question.
Here, S.P. = 6300, M.P. = ?
D_{1} = 25/2 %, D_{2} = 10%S.P. = M.P. 100 − D_{1} 100 − D_{2} 100 100 6300 = M.P. 100 − 25/2 100 − 10 100 100 ⇒ 6300 = M.P. 175 90 200 100 ⇒ M.P. = 6300 × 200 ×100 175 × 90
⇒ M.P. = ₹ 8000
 Two successive discounts of 10% and 5%, in this order, are given on a bill of ₹ 110. Find the net amount of money payable to clear the bill. (answer to the nearest rupee)

 ₹ 94
 ₹ 95
 ₹ 96
 ₹ 97

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Use the below formula to calculate the Single equivalent discount.
Single equivalent discount = D_{1} + D_{2} − D_{1}× D_{2} % 100 Single equivalent discount = 10 + 5 − 10 × 5 % 100 Correct Option: A
Use the below formula to calculate the Single equivalent discount.
Single equivalent discount = D_{1} + D_{2} − D_{1}× D_{2} % 100 Single equivalent discount = 10 + 5 − 10 × 5 % 100
Single equivalent discount = 14.5 %
∴ Amount to be paid = (100 – 14.5)% of 110⇒ Amount to be paid = 110 ×85.5 = ₹ 94.05 100
⇒ Amount to be paid ≈ ₹ 94