Discount


  1. A scooter is sold at three successive discounts of 10%, 5% and 2%. If the marked price of the scooter is Rs. 18,000, find its net selling price.
    1. Rs. 15028.20
    2. Rs. 15082.00
    3. Rs. 15082.20
    4. Rs. 15080.00

  1. View Hint View Answer Discuss in Forum

    According to given question.
    Here, D1 = 10%, D2 = 5%, D3 = 2%
    Net Selling Price of Sccoter

    = Marked Price x
    100 − D1
    100 − D2
    100 − D3
    100100100


    Correct Option: C

    According to given question.
    Here, D1 = 10%, D2 = 5%, D3 = 2%
    Net Selling Price of Sccoter

    = Marked Price x
    100 − D1
    100 − D2
    100 − D3
    100100100

    Net selling price of scooter.
    = Rs. 18000 ×
    90
    ×
    95
    ×
    98
    100100100

    = Rs. 15082.2


  1. The difference between successive discounts of 40% followed by 30% and 45% followed by 20% on the marked price of an article is Rs. 12. The marked price of the article is :
    1. ₹ 800
    2. ₹ 400
    3. ₹ 200
    4. ₹ 600

  1. View Hint View Answer Discuss in Forum

    Single equivalent discount for 40% and 30%

    = 40 + 30 −
    40 × 30
    %
    100

    = (70 – 12)% = 58%
    Single equivalent discount for 45% and 20%
    = 45 + 20 −
    45 × 20
    %
    100

    = (65 – 9)% = 56%
    Let the marked price be Rs. M.
    According to the question,
    M × (58 – 56)% = 12

    Correct Option: D

    Single equivalent discount for 40% and 30%

    = 40 + 30 −
    40 × 30
    %
    100

    = (70 – 12)% = 58%
    Single equivalent discount for 45% and 20%
    = 45 + 20 −
    45 × 20
    %
    100

    = (65 – 9)% = 56%
    Let the marked price be Rs. M.
    According to the question,
    M × (58 – 56)% = 12
    ⇒ 
    M × 2
    = 12
    100

    ⇒  M =
    1200
    = Rs. 600
    2



  1. A double bed is marked at ₹ 7,500. The shopkeeper allows successive discounts of 8%, 5% and 2% on it. What is the net selling price ?
    1. ₹ 6, 500
    2. ₹ 6,000
    3. ₹ 6,423.90
    4. ₹ 6,500.50

  1. View Hint View Answer Discuss in Forum

    As we know the formula for two successive discount.

    Single equivalent discount = D1 + D2
    D1 × D2
    %
    100

    Single equivalent discount for 8% and 5% = 8 + 5 −
    8 × 5
    %
    100

    Single equivalent discount for 8% and 5% = (13 – 0.4) = 12.6 %
    Similarly calculate other discount and Solve the question for Net Selling price of product.
    Alternate method to solve this question :
    According to given question.
    M.P. = ₹ 7500, S.P. = ?, D1 = 8%, D2 = 5%, D3 = 2%
    S.P = M.P.
    100 − D1
    100 − D2
    100 − D3
    100100100

    S.P = 7500
    100 − 8
    100 − 5
    100 − 2
    100100100

    Correct Option: C

    As we know the formula for two successive discount.

    Single equivalent discount = D1 + D2
    D1 × D2
    %
    100

    Single equivalent discount for 8% and 5% = 8 + 5 −
    8 × 5
    %
    100

    Single equivalent discount for 8% and 5% = 8 + 5 −
    8 × 5
    %
    100

    Single equivalent discount for 8% and 5% = (13 – 0.4) = 12.6 %
    Single equivalent disconut for 12.6% and 2% = 12.6 + 2 −
    12.6 × 2
    %
    100

    Single equivalent disconut for 12.6% and 2% = 14.6 – 0.252 = 14.348 %
    ∴  Net S.P = (100 – 14.348) % of 7500
    ∴  Net S.P =
    7500 × 85.652
    = ₹ 6423.90
    100

    Alternate method to solve this question :
    According to given question.
    M.P. = ₹ 7500, S.P = ?, D1 = 8%, D2 = 5%, D3 = 2%
    S.P = M.P.
    100 − D1
    100 − D2
    100 − D3
    100100100

    S.P = 7500
    100 − 8
    100 − 5
    100 − 2
    100100100

    S.P = 7500 ×
    92
    ×
    95
    ×
    98
    100100100

    S.P = ₹ 6423.90


  1. A plate was sold for 6,300 after giving two successive discounts of
    12
    1
    %   and 10%. Find the marked price.
    2
    1. ₹ 7,300
    2. ₹ 7,700
    3. ₹ 8,000
    4. ₹ 7,250

  1. View Hint View Answer Discuss in Forum

    Single equivalent discount for two successive discounts

    = x + y −
    xy
    %
    100

    =
    25
    + 10 −
    25 × 10
    %
    2100

    = ( 12.5 + 10 – 1.25 )%
    = 21.25 %
    If the marked price of the plate be ₹ M and solve this question further.

    Alternate method to solve this question :
    According to given question.
    Here, S.P. = 6300, M.P. = ?
    D1 = 25/2 %, D2 = 10%
    S.P. = M.P.
    100 − D1
    100 − D2
    100100

    6300 = M.P.
    100 − 25/2
    100 − 10
    100100

    ⇒  6300 = M.P.
    175
    90
    200100


    Correct Option: C

    Single equivalent discount for two successive discounts

    = x + y −
    xy
    %
    100

    =
    25
    + 10 −
    25 × 10
    %
    2100

    = ( 12.5 + 10 – 1.25 )%
    = 21.25 %
    If the marked price of the plate be ₹ M, then
    = (100 – 21.25 ) % of M = 6300
    ⇒  M ×
    78.75
    = 6300
    100

    ⇒  M =
    6300 × 100
    = ₹ 8000
    78.75

    Alternate method to solve this question :
    According to given question.
    Here, S.P. = 6300, M.P. = ?
    D1 = 25/2 %, D2 = 10%
    S.P. = M.P.
    100 − D1
    100 − D2
    100100

    6300 = M.P.
    100 − 25/2
    100 − 10
    100100

    ⇒  6300 = M.P.
    175
    90
    200100

    ⇒  M.P. =
    6300 × 200 ×100
    175 × 90

    ⇒  M.P. = ₹ 8000



  1. Two successive discounts of 10% and 5%, in this order, are given on a bill of ₹ 110. Find the net amount of money payable to clear the bill. (answer to the nearest rupee)
    1. ₹ 94
    2. ₹ 95
    3. ₹ 96
    4. ₹ 97

  1. View Hint View Answer Discuss in Forum

    Use the below formula to calculate the Single equivalent discount.

    Single equivalent discount = D1 + D2
    D1× D2
    %
    100

    Single equivalent discount = 10 + 5 −
    10 × 5
    %
    100

    Correct Option: A

    Use the below formula to calculate the Single equivalent discount.

    Single equivalent discount = D1 + D2
    D1× D2
    %
    100

    Single equivalent discount = 10 + 5 −
    10 × 5
    %
    100

    Single equivalent discount = 14.5 %
    ∴  Amount to be paid = (100 – 14.5)% of 110
    ⇒  Amount to be paid =
    110 ×85.5
    = ₹ 94.05
    100

    ⇒  Amount to be paid ≈ ₹ 94