Discount


  1. A shopkeeper earns a profit of 12% on selling a book at 10% discount on the printed price. The ratio of the cost price and the printed price of the book is









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    Let the CP of book = ₹ P
    Then, SP of book = {(100 + 12) x P}/100 = 112P/100
    Now, the printed price = ₹ Q
    Then, after discount,
    the SP = (100 - 10)Q/100 = 90Q/100
    Since, both SP are same.
    Then, 112P/100 = 90Q/100

    Correct Option: A

    Let the CP of book = ₹ P
    Then, SP of book = {(100 + 12) x P}/100 = 112P/100
    Now, the printed price = ₹ Q
    Then, after discount,
    the SP = (100 - 10)Q/100 = 90Q/100
    Since, both SP are same.
    Then, 112P/100 = 90Q/100
    ⇒ P/Q = 45/56
    ⇒ 45 : 56


  1. A shopkeeper allows 10% discount on goods when he sells without credit. Cost price of his goods is 80% of his selling price. If he sells his goods by cash, then his profit is









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    Let Marked price of article= Rs. p

    ∴ S.P. of article =
    90p
    100

    = Rs.
    9p
    10

    ∴  C.P. =
    80p × 9p
    =
    36p
    100 × 1050

    ∴  Gain =
    9p
    36p
    1050

    Correct Option: C

    Let Marked price of article= Rs. p

    ∴ S.P. of article =
    90p
    100

    = Rs.
    9p
    10

    ∴  C.P. =
    80p × 9p
    =
    36p
    100 × 1050

    ∴  Gain =
    9p
    36p
    1050

    Gain =
    45p − 36p
    = Rs.
    9p
    5050

    ∴  Gain %=
    9p/50
    × 100 = 25 %
    36p/50



  1. The marked price is 20% higher than cost price. A discount of 20% is given on the marked price. By this type of sale, there is









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    Let Cost price = ₹ 100
    Marked price = ₹ 120

    Selling price =
    120 × 80
    = ₹ 96
    100

    2nd method to solve this question.
    Here, r = 20%, r1 = 20%
    Loss % =
    r ×(100 − r1)
    − r1
    100

    Correct Option: A

    Let Cost price = ₹ 100
    Marked price = ₹ 120

    Selling price =
    120 × 80
    = ₹ 96
    100

    ∴  Loss = 4 and loss percent = 4%
    2nd method to solve this question.
    Here, r = 20%, r1 = 20%
    Loss % =
    r ×(100 − r1)
    − r1
    100

    Loss % =
    20 × (100 − 20)
    − 20
    100

    Loss % =
    20 × 80
    − 20
    100

    Loss % = –4% (–ve sign shows loss)
    Required Loss % = 4% loss


  1. A dealer marks his goods at 25% above the cost price and allows a discount of 10% for cash payment. His profit % is :









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    Let Cost price of article = ₹ 100
    Marked price = ₹ 125

    ∴  S.P. =
    125 × 90
    = ₹ 112.5
    100

    ∴  Gain = 112.5 – 100 = 12.5
    ⇒  Gain percent = 12.5%
    2nd method to solve this question.
    Here, r = 25%, r1 = 10%
    Profit % =
    r ×(100 − r1)
    − r1
    100

    Correct Option: C

    Let Cost price of article = ₹ 100
    Marked price = ₹ 125

    ∴  S.P. =
    125 × 90
    = ₹ 112.5
    100

    ∴  Gain = 112.5 – 100 = 12.5
    ⇒  Gain percent = 12.5%
    2nd method to solve this question.
    Here, r = 25%, r1 = 10%
    Profit % =
    r ×(100 − r1)
    − r1
    100

    Profit % =
    25 × (100 − 10)
    − 10
    100

    Profit % =
    25 × 90
    − 10
    100

    Required Profit % = 22.5 – 10 = 12.5%



  1. To gain 8% after allowing a discount of 10%, by what percent cost price should be hiked in the list price ?









  1. View Hint View Answer Discuss in Forum

    Let the cost price be ₹ 100 and marked price be p.

    ∴ 
    p × 90
    = 108
    100

    ⇒ 
    9p
    = 108
    10

    2nd method to solve this question.
    Here, Gain % = 8%,, r1 = 10%, r = ?
    Gain % =
    r ×(100 − r1)
    − r1
    100

    Correct Option: D

    Let the cost price be ₹ 100 and marked price be p.

    ∴ 
    p × 90
    = 108
    100

    ⇒ 
    9p
    = 108
    10

    ⇒  p =
    108 × 10
    = 120
    9

    Required Percent = 20%
    2nd method to solve this question.
    Here, Gain % = 8%,, r1 = 10%, r = ?
    Gain % =
    r ×(100 − r1)
    − r1
    100

    8 =
    r × (100 − 10)
    − 10
    100

    8 =
    r × 90
    − 10
    9

    18 =
    r × 9
    = 20%
    9