Discount
- If a shopkeeper marks the price of goods 50% more than their cost price and allows a discount of 40%, what is his gain or loss percent ?
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Let C.P. of article = ₹ 100
Marked price = ₹ 150S.P. = 150 × 60 = ₹ 90 100
2nd method to solve this question.
Here, r = 50%, r1 = 40%His loss % = r ×(100 − r1) − r1 100
Correct Option: B
Let C.P. of article = ₹ 100
Marked price = ₹ 150S.P. = 150 × 60 = ₹ 90 100
Loss = 100 – 90 = ₹ 10 i.e. 10%
2nd method to solve this question.
Here, r = 50%, r1 = 40%His loss % = r ×(100 − r1) − r1 100 Loss % = 50 × (100 − 40) − 40 100 Loss % = 50 × 60 − 40 100
Loss % = –10% (–ve sign shows loss)
Required Loss % = 10% loss
- A trader marks the sale price 25% more on cost price and gives a 10% discount at the time of selling. The gain % is
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Let us assume the C.P. of article be Rs. 100.
According to question.
∴ Its marked price = Rs. 125S.P. = Rs. 125 × 90 = Rs. 112.5 100
2nd Method to solve this question.Profit % = x + y + xy % 100
where x = 25%; y = –10%Correct Option: A
Let us assume the C.P. of article be Rs. 100.
According to question.
∴ Its marked price = Rs. 125S.P. = Rs. 125 × 90 = Rs. 112.5 100
∴ Profit % = 12.5 %
2nd Method to solve this question.Profit % = x + y + xy % 100
where x = 25%; y = –10%Profit % = 25 − 10 − 25 × 10 % 100
Profit % = 12.5%
- A tradesman marks his goods 10% above his cost price. If he allows his customers 10% discount on the marked price, how much profit or loss does he make, if any?
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As we know that ,
Required loss = 10 × 10 = 1% 100
2nd method to solve this question.
Here, r = 10% and r1 = 10%
⇒ Required profit or loss= r ×(100 − r1) −r1 100 = 10 ×(100 − 10) −10 100
Correct Option: B
As we know that ,
Required loss = 10 × 10 = 1% 100
2nd method to solve this question.
Here, r = 10% and r1 = 10%⇒ Required profit or loss = r ×(100 − r1) −r1 100 = 10 ×(100 − 10) −10 100
Required profit or loss = 9 – 10
Required profit or loss = –1% (–ve sign shows loss)
Required profit or loss = 1% loss
- A dinner set is quoted for Rs. 1500. A customer pays Rs. 1173 for it. If the customer got a series of two discounts and the rate of first discount is 15% then the rate of second discount was
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According to the question,
First discount = 15%
S.P. of dinner set after first discount = (100 – 15)% of Rs. 1500= Rs. 1500 × 85 = Rs. 1275 100
Second discount = Rs. ( 1275 – 1173 ) = Rs. 102Correct Option: D
According to the question,
First discount = 15%
S.P. of dinner set after first discount = (100 – 15)% of Rs. 1500= Rs. 1500 × 85 = Rs. 1275 100
Second discount = Rs. ( 1275 – 1173 ) = Rs. 102
If second discount be d %, then∴ 1275 × d = 102 100 ⇒ d = 102 × 100 = 8% 1275
- A dealer marks his goods at 40 % above the cost price and allows a discount of 20 % on the marked price. The dealer has a
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Let the CP of article be ₹ 100.
∴ Marked price = ₹ 140S.P. = 140 × 80 = ₹ 112 100
2nd Method to solve this question.
Here, r = 40%, r1 = 20%Required profit or loss % = r ×(100 − r1) − r1 100
Correct Option: D
Let the CP of article be ₹ 100.
∴ Marked price = ₹ 140S.P. = 140 × 80 = ₹ 112 100
∴ Gain percent = 12%
2nd Method to solve this question.
Here, r = 40%, r1 = 20%Required profit or loss % = r ×(100 − r1) − r1 100 Required profit or loss % = 40 × (100 − 20) − 20 100 Required profit or loss % = 40 × 80 −20 100
Required profit or loss % = 32 – 20 = 12% profit