Simple interest
- The amount to be paid, when principal = Rs. 2000, rate of simple interest (R) = 5%, T = 2 years, is :
-
View Hint View Answer Discuss in Forum
Here , Principal = Rs. 2000, rate (R) = 5% , T = 2 years,
SI = Principal × Time × Rate 100 SI = 2000 × 2 × 5 100
SI = Rs. 200
Correct Option: C
Here , Principal = Rs. 2000, rate (R) = 5% , T = 2 years,
SI = Principal × Time × Rate 100 SI = 2000 × 2 × 5 100
SI = Rs. 200
∴ Required amount = Principle + SI = Rs. (2000 + 200) = Rs. 2200
- The rate of simple interest for which Rs. 6,000 will amount to Rs. 6,900 in 3 years is
-
View Hint View Answer Discuss in Forum
We know that ,
S.I. = Amount – Principal
S.I. = Rs. (6900 – 6000) = Rs. 900∴ Rate = Simple Interest × 100 Principal × Time
Correct Option: A
We know that ,
S.I. = Amount – Principal
S.I. = Rs. (6900 – 6000) = Rs. 900∴ Rate = Simple Interest × 100 Principal × Time Rate = 900 × 100 6000 × 3
Rate = 5% per annum
- A sum of money becomes 7/6 of itself in 3 years at a certain rate of simple interest. The rate per annum is :
-
View Hint View Answer Discuss in Forum
Let Principal = P
Amount = 7P 6 S.I. = 7P - P = P 6 6 ∴ R = SI × 100 = P × 100 Principal × Time 6 × P × 3 R = 50 = 5 5 % 9 9
Second method to solve this question :R% = (7/6 - 1) × 100% 3
Correct Option: A
Let Principal = P
Amount = 7P 6 S.I. = 7P - P = P 6 6 ∴ R = SI × 100 = P × 100 Principal × Time 6 × P × 3 R = 50 = 5 5 % 9 9
Second method to solve this question :R% = (7/6 - 1) × 100% 3 R = 1 × 100% 18 R = 50 % 9 R = 5 5 % 9
- A person lent 5,000 partly at the rate of 4 percent and partly at the rate of 5 percent per annum simple interest. The total interest after 2 years is 440. To find the sum of money lentat each of the above rates, 5,000 is to be divided in the ratio :
-
View Hint View Answer Discuss in Forum
Let the sum of p be lent at the rate of 4% and (5000 – p) at the rate of 5%
we know that ,SI = P × R × T 100
From question , we havep × 4 × 2 + (5000 - p) × 5 × 2 = 440 100 100
Correct Option: D
Let the sum of p be lent at the rate of 4% and (5000 – p) at the rate of 5%
we know that ,SI = P × R × T 100
From question , we havep × 4 × 2 + (5000 - p) × 5 × 2 = 440 100 100
⇒ 8p + 50000 – 10p = 44000
⇒ 2p = 50000 – 44000 = 6000
⇒ p = ₹ 3000
∴ (5000 – p) = (5000 – 3000) = 2000
Now, Required ratio = First part : second part = 3000 : 2000 = 3 : 2
- Find the interest on ₹ 1460 at 10% from 5th February, 1992 to 25th April, 1992.
-
View Hint View Answer Discuss in Forum
Given that , P = ₹ 1460
R = 10%
1992 is a leap year .
∴ T = (24 + 31 + 25) days = 80 days
As we know that ,I = PRD 36500
Correct Option: A
Given that , P = ₹ 1460
R = 10%
1992 is a leap year .
∴ T = (24 + 31 + 25) days = 80 days.
As we know that ,I = PRD 36500 I = 1460 × 10 × 80 36500
I = ₹ 32.
Note : We have excluded 5th February but included 25th