Simple interest


  1. The amount to be paid, when principal = Rs. 2000, rate of simple interest (R) = 5%, T = 2 years, is :









  1. View Hint View Answer Discuss in Forum

    Here , Principal = Rs. 2000, rate (R) = 5% , T = 2 years,

    SI =
    Principal × Time × Rate
    100

    SI =
    2000 × 2 × 5
    100

    SI = Rs. 200

    Correct Option: C

    Here , Principal = Rs. 2000, rate (R) = 5% , T = 2 years,

    SI =
    Principal × Time × Rate
    100

    SI =
    2000 × 2 × 5
    100

    SI = Rs. 200
    ∴ Required amount = Principle + SI = Rs. (2000 + 200) = Rs. 2200


  1. The rate of simple interest for which Rs. 6,000 will amount to Rs. 6,900 in 3 years is









  1. View Hint View Answer Discuss in Forum

    We know that ,
    S.I. = Amount – Principal
    S.I. = Rs. (6900 – 6000) = Rs. 900

    ∴ Rate =
    Simple Interest × 100
    Principal × Time

    Correct Option: A

    We know that ,
    S.I. = Amount – Principal
    S.I. = Rs. (6900 – 6000) = Rs. 900

    ∴ Rate =
    Simple Interest × 100
    Principal × Time

    Rate =
    900 × 100
    6000 × 3

    Rate = 5% per annum



  1. A sum of money becomes 7/6 of itself in 3 years at a certain rate of simple interest. The rate per annum is :









  1. View Hint View Answer Discuss in Forum

    Let Principal = P

    Amount =
    7P
    6

    S.I. =
    7P
    - P =
    P
    66

    ∴ R =
    SI × 100
    =
    P × 100
    Principal × Time6 × P × 3

    R =
    50
    = 5
    5
    %
    99

    Second method to solve this question :
    R% =
    (7/6 - 1) × 100%
    3

    Correct Option: A

    Let Principal = P

    Amount =
    7P
    6

    S.I. =
    7P
    - P =
    P
    66

    ∴ R =
    SI × 100
    =
    P × 100
    Principal × Time6 × P × 3

    R =
    50
    = 5
    5
    %
    99

    Second method to solve this question :
    R% =
    (7/6 - 1) × 100%
    3

    R =
    1
    × 100%
    18

    R =
    50
    %
    9

    R = 5
    5
    %
    9


  1. A person lent 5,000 partly at the rate of 4 percent and partly at the rate of 5 percent per annum simple interest. The total interest after 2 years is 440. To find the sum of money lentat each of the above rates, 5,000 is to be divided in the ratio :









  1. View Hint View Answer Discuss in Forum

    Let the sum of p be lent at the rate of 4% and (5000 – p) at the rate of 5%
    we know that ,

    SI =
    P × R × T
    100

    From question , we have
    p × 4 × 2
    +
    (5000 - p) × 5 × 2
    = 440
    100100

    Correct Option: D

    Let the sum of p be lent at the rate of 4% and (5000 – p) at the rate of 5%
    we know that ,

    SI =
    P × R × T
    100

    From question , we have
    p × 4 × 2
    +
    (5000 - p) × 5 × 2
    = 440
    100100

    ⇒ 8p + 50000 – 10p = 44000
    ⇒ 2p = 50000 – 44000 = 6000
    ⇒ p = ₹ 3000
    ∴ (5000 – p) = (5000 – 3000) = 2000
    Now, Required ratio = First part : second part = 3000 : 2000 = 3 : 2



  1. Find the interest on ₹ 1460 at 10% from 5th February, 1992 to 25th April, 1992.









  1. View Hint View Answer Discuss in Forum

    Given that , P = ₹ 1460
    R = 10%
    1992 is a leap year .
    ∴ T = (24 + 31 + 25) days = 80 days
    As we know that ,

    I =
    PRD
    36500

    Correct Option: A

    Given that , P = ₹ 1460
    R = 10%
    1992 is a leap year .
    ∴ T = (24 + 31 + 25) days = 80 days.
    As we know that ,

    I =
    PRD
    36500

    I =
    1460 × 10 × 80
    36500

    I = ₹ 32.
    Note : We have excluded 5th February but included 25th