Simple interest
- At the rate of 81/2% per annum simple interest, a sum of ₹ 5800 will earn how much interest in 2 yr 3 months ?
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Time = 2 yr 3 months = 21/4 yr = 9/4 yr
∴ SI = [5800 x (17/2) x (9/4)] / 100Correct Option: B
Time = 2 yr 3 months = 21/4 yr = 9/4 yr
∴ SI = [5800 x (17/2) x (9/4)] / 100
= 8874/8
= ₹ 1109.25
= ₹ 1109
- A certain sum becomes 3 fold at 4% annual rate of interest. At what rate, it will become 6 fold ?
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Here, n = 3, m = 6, R1 = 4%
∴ R2 = [(m - 1)/(n - 1)] x R1Correct Option: A
Here, n = 3, m = 6, R1 = 4%
∴ R2 = [(m - 1)/(n - 1)] x R1
= [(6 - 1)/(3 - 1)] x 4
=(5/2) x 4
= 10%
- Kriya deposits an amount of ₹ 65800 to obtain a simple interest at the rate of 14% per annum for 4 yr. What total amount will Kriya get at the end of 4 yr ?
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Here, P = ₹ 65800, R = 14% T = 4 yr
Hence, SI = (65800 x 14 x 4) / 100 =₹ 36848Correct Option: A
Here, P = ₹ 65800, R = 14% T = 4 yr
Hence, SI = (65800 x 14 x 4) / 100 =₹ 36848
∴ Required amount = P + SI
= 65800 + 36848
= ₹ 102648
- In a certain time, a sum becomes 4 times at the rate of 5% per annum. At what rate of simple interest, the same sum becomes 8 times in the same duration ?
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Let the sum be p
Then, for R = 5%
SI = (4p - p) = 3p
∴ 3p = (P x 5 x T)/100 = PT/20
⇒ T = 60 yr
Again, for another rate (R)
SI = (8P - P) = 7P
∴ 7P = (P x R x 60)/100Correct Option: C
Let the sum be p
Then, for R = 5%
SI = (4p - p) = 3p
∴ 3p = (P x 5 x T)/100 = PT/20
⇒ T = 60 yr
Again, for another rate (R)
SI = (8P - P) = 7P
∴ 7P = (P x R x 60)/100
⇒ R = (7 x 100)/60 = 35/3%
= 112/3 %
- In what time does a sum of money become four fold at the simple interest ratio of 10% per annum ?
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Here, n = 4, R = 10, T = ?
According to the formula,
R = 100 (n - 1)/TCorrect Option: B
Here, n = 4, R = 10, T = ?
According to the formula,
R = 100 (n - 1)/T
⇒ 10 = [100(4 - 1)]/T = (100 x 3)/T
∴ T = 30 yr