Simple interest
- A sum of Rs. 7,930 is divided into three parts and given on loan at 5% simple interest to A, B and C for 2, 3 and 4 years respectively. If the amounts of all three are equal after their respective periods of loan, then A received a loanof
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Let the loans taken by A, B and C be Rs. p, Rs. q and Rs. r respectively.
∴ p + q + r = Rs. 7930
We can find the required answer with the help of given formula ,S.I = Principal × Time × Rate 100
According to the question,p + p × 2 × 5 = q + q × 3 × 5 = r + r × 4 × 5 100 100 100 ⇒ 100p + 10p = 100q + 15q = 100r + 20r 100 100 100
⇒ 110p = 115q = 120r
⇒ 22p = 23q = 24r⇒ 22p = 23q = 24r 6072 6072 6072
[LCM of 22, 23 and 24 = 6072]⇒ p = q = r 276 264 253
Correct Option: B
Let the loans taken by A, B and C be Rs. p, Rs. q and Rs. r respectively.
∴ p + q + r = Rs. 7930
We can find the required answer with the help of given formula ,S.I = Principal × Time × Rate 100
According to the question,p + p × 2 × 5 = q + q × 3 × 5 = r + r × 4 × 5 100 100 100 ⇒ 100p + 10p = 100q + 15q = 100r + 20r 100 100 100
⇒ 110p = 115q = 120r
⇒ 22p = 23q = 24r⇒ 22p = 23q = 24r 6072 6072 6072
[LCM of 22, 23 and 24 = 6072]⇒ p = q = r 276 264 253
∴ p : q : r = 276 : 264 : 253
Sum of terms of ratio = 276 + 264 + 253 = 793∴ A’s loan = 276 × 7930 = Rs. 2760 793
- Ram bought a bike for Rs. 60,000. He paid Rs. 10000 cash down and the rest at the end of 2 years at 15% simple interest. How much more did he pay as simple interest ?
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On the basis of given in question ,
Principal = Rs. (60000 – 10000) = Rs. 50000
We can find the required answer with the help of given formula ,SI = P × R × T 100
Correct Option: A
On the basis of given in question ,
Principal = Rs. (60000 – 10000) = Rs. 50000
We can find the required answer with the help of given formula ,SI = P × R × T 100 S.I = 50000 × 15 × 2 100
SI = Rs. 15000
- Nitin borrowed some money at the rate of 6% p.a. for the first three years, 9% p.a. for the next five years and 13% p.a. for the period beyond eight years. If the total interest paid by him at the end of eleven years is 8,160, the money borrowed by him (in ) was
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If the sum of money be p, then
From the question ,⇒ p × 6 × 3 + p × 5 × 9 + p × 3 × 13 = 8160 100 100 100
Correct Option: C
If the sum of money be p, then
From the question ,⇒ p × 6 × 3 + p × 5 × 9 + p × 3 × 13 = 8160 100 100 100
⇒ 18p + 45p + 39p = 816000
⇒ 102p = 816000
⇒ p = 816000 ÷ 102 = ₹ 8000
- If a man receives on one-fourth of his capital 3% interest, on two third 5% and on the remainder 11%, the percentage he receives on the whole is
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According to question , we have
Required percent = 1 × 3 + 2 × 5 + 
1 - 1 - 2 
× 11 4 3 4 3
Correct Option: B
According to question , we have
Required percent = 1 × 3 + 2 × 5 + 1 - 1 - 2 × 11 4 3 4 3 Required percent = 3 + 10 + 11 = 9 + 40 + 11 = 5% 4 3 12 12
- Arun lends ₹ 20,000 to two of his friends. He gives ₹ 12,000 to the first at 8% p.a. simple interest. Arun wants to make a profit of 10% on the whole. The simple interest rate at which he should lend the remaining sum of money to the second friend is
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We know that ,
∴ SI = P × R × T 100
According to question ,S.I. on 12000 = 12000 × 8 × 1 = ₹ 960 100
Desired gain on ₹ 20000
= 20000 × (10 ÷ 100) = ₹ 2000
∴ S.I. on ₹ 8000 = 2000 – 960 = ₹ 1040
Correct Option: D
We know that ,
∴ SI = P × R × T 100
According to question ,S.I. on 12000 = 12000 × 8 × 1 = ₹ 960 100
Desired gain on ₹ 20000
= 20000 × (10 ÷ 100) = ₹ 2000
∴ S.I. on ₹ 8000 = 2000 – 960 = ₹ 1040∴ Rate = SI × 100 Principal × Time Rate = 1040 × 100 800
Rate = 13% per annum
