Simple interest
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Prakash lends a part of ₹20,000 at 8% simple interest and remaining at 4 % 3
simple interest. His total income after a year was ₹800. Find the sum lent at 8%.
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According to question ,
Let Amount lent at 8% rate of interest = ₹ p∴ Amount lent at 4 % rate of interest = (20,000 – p) 3 ∴ SI = Principal × Time × Rate 100 ∴ p × 8 × 1 + (20000 - p) × ( 4/3 ) × 1 = 800 100 100 ⇒ 2p + 20000 - p = 800 25 75 ⇒ 6p + 20000 - p = 800 75
Correct Option: A
According to question ,
Let Amount lent at 8% rate of interest = ₹ p∴ Amount lent at 4 % rate of interest = (20,000 – p) 3 ∴ SI = Principal × Time × Rate 100 ∴ p × 8 × 1 + (20000 - p) × ( 4/3 ) × 1 = 800 100 100 ⇒ 2p + 20000 - p = 800 25 75 ⇒ 6p + 20000 - p = 800 75
⇒ 5p + 20,000 = 75 × 800 = 60,000
⇒ 5p = 60,000-20,000 = 40,000
⇒ p = 40000 ÷ 5 = 8000
- The simple interest on ₹4,000 in 3 years at the rate of y% per annum equals the simple interest on ₹5,000 at the rate of 12% per annum in 2 years. The value of y is
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We can find the required answer with the help of given formula ,
SI = Principal × Time × Rate 100 ∴ 4000 × 3 × y = 5000 × 2 × 12 100 100
Correct Option: A
We can find the required answer with the help of given formula ,
SI = Principal × Time × Rate 100 ∴ 4000 × 3 × y = 5000 × 2 × 12 100 100 ⇒ y = 5 × 2 × 12 4 × 3
y = 10% per annum
- The rate of interest per annum at which the total simple interest of a certain capital for 1 year is equal to the total simple interest of the same capital at the rate of 5% per annum for 2 years, is
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Let the capital be P .
We know that ,SI = P × R × T 100
According to question ,P × r × 1 = P × 5 × 2 100 100
Correct Option: B
Let the capital be P .
We know that ,SI = P × R × T 100
According to question ,P × r × 1 = P × 5 × 2 100 100
[ ∵ Capital is same in both cases]
⇒ r × 1 = 5 × 2
⇒ r = 10%
- In how many years will the simple interest on a sum of money be equal to the
principal at the rate of 16 2 % per annum ? 3
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Let the principal be p.
We can find the required time with the help of given formula ,Time = Simple Interest × 100 Principal × Rate
Correct Option: C
Let the principal be p.
We can find the required time with the help of given formula ,Time = Simple Interest × 100 Principal × Rate Time = p × 100 × 3 = 6 Years. p × 50
- A person deposited ₹500 for 4 years and ₹600 for 3 years at the same rate of simple interest in a bank. Altogether he received ₹190 as interest. The rate of simple interest per annum was
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Let 'r' be the rate of interest .
As we know that ,SI = P × R × T 100
According to question ,190 = 500 × 4 × r + 600 × 3 × r 100 100
Correct Option: B
Let 'r' be the rate of interest .
As we know that ,SI = P × R × T 100
According to question ,190 = 500 × 4 × r + 600 × 3 × r 100 100
⇒ 20r + 18r = 190
⇒ 38r = 190
⇒ r = 190 ÷ 38 = 5%
