Simple interest


  1. Ram lent ₹ 1200 to Shyam for 5 years and ₹ 1500 to Mohan for 2 years received altogether ₹ 900 as interest. Find the rate per annum.









  1. View Hint View Answer Discuss in Forum

    As per the given in question ,
    SI = SI1 + SI2

    SI =
    P1RT1
    +
    P2RT2
    100 100

    SI =
    R
    (P1T1 + P2T2)
    100

    or, R =
    100 × I
    P1T1 + P2T2

    Here, SI = ₹ 900 , P1 = ₹ 1200 , T1 = 5 years , P2 = ₹ 1500 , T2 = 2 years
    Rate =
    100 × 900
    (1200 × 5) + (1500 × 2)

    Correct Option: D

    As per the given in question ,
    SI = SI1 + SI2

    SI =
    P1RT1
    +
    P2RT2
    100 100

    SI =
    R
    (P1T1 + P2T2)
    100

    or, R =
    100 × I
    P1T1 + P2T2

    Here, SI = ₹ 900 , P1 = ₹ 1200 , T1 = 5 years , P2 = ₹ 1500 , T2 = 2 years
    Rate =
    100 × 900
    (1200 × 5) + (1500 × 2)

    Rate =
    90000
    9000

    R = 10%.
    Note : In case of more than two investment, sum the products of principal and time of each case.


  1. Find the amount Ram will get after 2 years when he invests ₹ 15000 at 15% interest.









  1. View Hint View Answer Discuss in Forum

    Here, P = ₹ 15000 , R = 15% , T = 2 years
    We can find the required answer with the help of given formula ,

    A = P
    100 + RT
    100

    Amount = 15000
    100 + 15 × 2
    100

    Correct Option: B

    Here, P = ₹ 15000 , R = 15% , T = 2 years
    We can find the required answer with the help of given formula ,

    A = P
    100 + RT
    100

    Amount = 15000
    100 + 15 × 2
    100

    A = 15000 ×
    130
    100

    A = ₹ 19500.



  1. Find the interest on ₹ 1460 at 10% from 5th February, 1992 to 25th April, 1992.









  1. View Hint View Answer Discuss in Forum

    Given that , P = ₹ 1460
    R = 10%
    1992 is a leap year .
    ∴ T = (24 + 31 + 25) days = 80 days
    As we know that ,

    I =
    PRD
    36500

    Correct Option: A

    Given that , P = ₹ 1460
    R = 10%
    1992 is a leap year .
    ∴ T = (24 + 31 + 25) days = 80 days.
    As we know that ,

    I =
    PRD
    36500

    I =
    1460 × 10 × 80
    36500

    I = ₹ 32.
    Note : We have excluded 5th February but included 25th


  1. 4 years, ₹ 6000 amounts to ₹ 8,000. In what time at the same rate will ₹ 525 amount to 700 ?









  1. View Hint View Answer Discuss in Forum

    Case-I,
    Simple Interest = 8000 – 6000 = Rs. 2000

    Rate =
    Simple Interest × 100
    Principal × Time

    Rate =
    2000 × 100
    =
    25
    %
    6000 × 43

    ∴ Case-II,
    Time =
    Simple Interest × 100
    Principal × Rate

    Correct Option: C

    Case-I,
    Simple Interest = 8000 – 6000 = Rs. 2000

    Rate =
    Simple Interest × 100
    Principal × Time

    Rate =
    2000 × 100
    =
    25
    %
    6000 × 43

    ∴ Case-II,
    Time =
    Simple Interest × 100
    Principal × Rate

    Time =
    175 × 100
    = 4 Years.
    525 ×
    25
    3



  1. A person on retirement gets Rs. 3,20,000 from his gratuity and P.F. He wants to invest this amount in Post Office and Bank in such a way that he earns a total interest of Rs. 27,600 every year. If the annual rate of interest in Post Office and Bank be respectively 9% and 8%, What are the amounts invested in Post Office and Bank respectively ?









  1. View Hint View Answer Discuss in Forum

    Let the amount in Post office be Rs. p.
    ∴ Amount in Bank = Rs. (320000 – p)
    We can find the SI with the help of given formula ,

    SI =
    Principal × Time × Rate
    100

    p × 9
    +
    (32000 - p) × 8
    = 27600
    100 100

    Correct Option: A

    Let the amount in Post office be Rs. p.
    ∴ Amount in Bank = Rs. (320000 – p)
    We can find the SI with the help of given formula ,

    SI =
    Principal × Time × Rate
    100

    p × 9
    +
    (32000 - p) × 8
    = 27600
    100 100

    ⇒ 9p + 2560000 – 8p= 2760000
    ⇒ p = 2760000 – 2560000 = Rs. 200000
    ∴ Amount in bank = Rs. (320000 – 200000) = Rs. 120000