Simple interest
 The sum of money, that will give 1 as interest per day at the rate of 5% per annum simple interest is

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According to question ,
The sum of money will give ₹365 as simple interest in a year.⇒ S.I = PRT 100 ⇒ 365 = P × 5 × 1 100
Correct Option: D
According to question ,
The sum of money will give ₹365 as simple interest in a year.⇒ S.I = PRT 100 ⇒ 365 = P × 5 × 1 100 P = 365 × 100 = ₹7300 5
 The simple interest on ₹7,300 from 11 May, 1987 to 10 September, 1987 (both days included) at 5% per annum is

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Given that , P = ₹7,300 , R = 5%
Time from 11 May to 10 September, 1987 = 21 + 30 + 31 + 31 + 10 = 123 days∴ Time = 123 days = 123 Year 365 ∴ SI = P × T × R 365 × 100
Correct Option: A
Given that , P = ₹7,300 , R = 5%
Time from 11 May to 10 September, 1987 = 21 + 30 + 31 + 31 + 10 = 123 days∴ Time = 123 days = 123 Year 365 ∴ SI = P × T × R 365 × 100 ⇒ SI = 7300 × 123 × 5 = ₹ 123 365 × 100

per annum exceeds thesimple interest on the same sum for 8 months atIf the simple interest on a certain sum of money for 15 months at 7 1 % 2 12 1 % per annum by ₹32.50, then the sum of money (in ₹) is : 2

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Let the sum be y.
We find the required answer with the help of given formula,SI = PTR 100 ⇒ y × (15 /12) × (15 / 2)  y × (8 / 12) × (25 / 2) = 32.50 100 100 ⇒ 25y = 32.50 2400
Correct Option: C
Let the sum be y.
We find the required answer with the help of given formula,SI = PTR 100 ⇒ y × (15 /12) × (15 / 2)  y × (8 / 12) × (25 / 2) = 32.50 100 100 ⇒ 25y = 32.50 2400 ⇒ y = 32.50 × 2400 = 3120 25
∴ Required sum = 3120
 A man had ₹16,000, part of which he lent at 4% and the rest at 5% per annum simple interest. If the total interest received was ₹700 in one year, the money lent at 4% per annum was

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Let the sum lent at 4% = Rs. y
∴ Amount at 5%= (16000 – y )
As we know that ,∴ SI = P × T × R 100
According to the question,y × 4 × 1  (16000  y) × 5 × 1 = 700 100 100
Correct Option: C
Let the sum lent at 4% = Rs. y
∴ Amount at 5%= (16000 – y )
As we know that ,∴ SI = P × T × R 100
According to the question,y × 4 × 1  (16000  y) × 5 × 1 = 700 100 100
⇒ 4y + 80000 – 5y = 70000
⇒ y = 80000 – 70000 = ₹ 10000

years and to 1,067.20 in 4 years. The rate of interest per annum is :A sum of money at simple interest amounts to 1,012 in 2 1 2

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According to question ,
Principal + S.I. for 5 yrs = ₹ 1012.............(i) 2
Principal + S.I. for 4 years = 1067.20 ...(ii)
Subtracting equation (i) from (ii)S.I. for 3 yrs = ₹ 55.20 2 ∴ S.I. for 5 yrs = 55.20 × 2 × 5 = ₹ 92 2 3 2
∴ Principal = Amount  SI = (1012 – 92) = ₹920∴ Rate = 92 × 100 920 × 5 2 Rate = 2 × 92 × 100 = 4% 920 × 5
Second method to solve this question :
Here , A_{2} = ₹ 1067.20 , T_{1} = 5 /2 years , A_{1} = ₹ 1012 , T_{2} = 4 yearsR = A_{1}  A_{2} × 100 A_{2}T_{1}  A_{1}T_{2}
Correct Option: C
According to question ,
Principal + S.I. for 5 yrs = ₹ 1012.............(i) 2
Principal + S.I. for 4 years = 1067.20 ...(ii)
Subtracting equation (i) from (ii)S.I. for 3 yrs = ₹ 55.20 2 ∴ S.I. for 5 yrs = 55.20 × 2 × 5 = ₹ 92 2 3 2
∴ Principal = Amount  SI = (1012 – 92) = ₹920∴ Rate = 92 × 100 920 × 5 2 Rate = 2 × 92 × 100 = 4% 920 × 5
Second method to solve this question :
Here , A_{2} = ₹ 1067.20 , T_{1} = 5 /2 years , A_{1} = ₹ 1012 , T_{2} = 4 yearsR = A_{1}  A_{2} × 100 A_{2}T_{1}  A_{1}T_{2} R = 1012  1067.20 × 100 1067.20 ×(5 ÷2)  1012 × 4 R =  55.2 × 100 (2668  4048) R =  55.2 × 100  1380
R = 4%