1. The sum of money, that will give 1 as interest per day at the rate of 5% per annum simple interest is
   

1. 1. ₹3650
      

   
   
   

   2. ₹36500
      

   
   
   

   3. ₹730
      

   
   
   

   4. ₹7300

   
   
   

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1. View Hint View Answer Discuss in Forum

   According to question ,
   The sum of money will give ₹365 as simple interest in a year.
   

   ⇒ S.I =	PRT
   	100

   
   

   ⇒ 365 =	P × 5 × 1
   	100

   
   

   Correct Option: D

   According to question ,
   The sum of money will give ₹365 as simple interest in a year.
   

   ⇒ S.I =	PRT
   	100

   
   

   ⇒ 365 =	P × 5 × 1
   	100

   
   

   P =	365 × 100	= ₹7300
   	5

   
   

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2. The simple interest on ₹7,300 from 11 May, 1987 to 10 September, 1987 (both days included) at 5% per annum is
   

1. 1. ₹123
      

   
   
   

   2. ₹103
      

   
   
   

   3. ₹200
      

   
   
   

   4. ₹223

   
   
   

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1. View Hint View Answer Discuss in Forum

   Given that , P = ₹7,300 , R = 5%
   Time from 11 May to 10 September, 1987 = 21 + 30 + 31 + 31 + 10 = 123 days
   

   ∴ Time = 123 days =	123	Year
   	365

   
   

   ∴ SI =	P × T × R
   	365 × 100

   
   

   Correct Option: A

   Given that , P = ₹7,300 , R = 5%
   Time from 11 May to 10 September, 1987 = 21 + 30 + 31 + 31 + 10 = 123 days
   

   ∴ Time = 123 days =	123	Year
   	365

   
   

   ∴ SI =	P × T × R
   	365 × 100

   
   

   ⇒ SI =	7300 × 123 × 5	= ₹ 123
   	365 × 100

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3. If the simple interest on a certain sum of money for 15 months at 7	1	%
   	2

   per annum exceeds thesimple interest on the same sum for 8 months at

   12	1	% per annum by ₹32.50, then the sum of money (in ₹) is :
   	2

   
   

1. 1. 312
      

   
   
   

   2. 312.50
      

   
   
   

   3. 3120
      

   
   
   

   4. 3120.50

   
   
   

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1. View Hint View Answer Discuss in Forum

   Let the sum be y.
   We find the required answer with the help of given formula,
   

   SI =	PTR
   	100

   
   

   ⇒	y × (15 /12) × (15 / 2)	-	y × (8 / 12) × (25 / 2)	= 32.50
   	100		100

   
   

   ⇒	25y	= 32.50
   	2400

   
   

   Correct Option: C

   Let the sum be y.
   We find the required answer with the help of given formula,
   

   SI =	PTR
   	100

   
   

   ⇒	y × (15 /12) × (15 / 2)	-	y × (8 / 12) × (25 / 2)	= 32.50
   	100		100

   
   

   ⇒	25y	= 32.50
   	2400

   
   

   ⇒ y =	32.50 × 2400	= 3120
   	25

   
   ∴ Required sum = 3120

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4. A man had ₹16,000, part of which he lent at 4% and the rest at 5% per annum simple interest. If the total interest received was ₹700 in one year, the money lent at 4% per annum was
   

1. 1. ₹12,000
      

   
   
   

   2. ₹8,000
      

   
   
   

   3. ₹10,000
      

   
   
   

   4. ₹6,000

   
   
   

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1. View Hint View Answer Discuss in Forum

   Let the sum lent at 4% = Rs. y
   ∴ Amount at 5%= (16000 – y )
   As we know that ,
   

   ∴ SI =	P × T × R
   	100

   
   According to the question,
   

   	y × 4 × 1	-	(16000 - y) × 5 × 1	= 700
   	100		100

   
   

   Correct Option: C

   Let the sum lent at 4% = Rs. y
   ∴ Amount at 5%= (16000 – y )
   As we know that ,
   

   ∴ SI =	P × T × R
   	100

   
   According to the question,
   

   	y × 4 × 1	-	(16000 - y) × 5 × 1	= 700
   	100		100

   
   ⇒ 4y + 80000 – 5y = 70000
   ⇒ y = 80000 – 70000 = ₹ 10000

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5. A sum of money at simple interest amounts to 1,012 in 2	1
   	2

   years and to 1,067.20 in 4 years. The rate of interest per annum is :
   

1. 1. 2.5%
      

   
   
   

   2. 3%
      

   
   
   

   3. 4%
      

   
   
   

   4. 5%

   
   
   

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1. View Hint View Answer Discuss in Forum

   According to question ,
   

   Principal + S.I. for	5	yrs = ₹ 1012.............(i)
   	2

   
   Principal + S.I. for 4 years = 1067.20 ...(ii)
   Subtracting equation (i) from (ii)
   

   S.I. for	3	yrs = ₹ 55.20
   	2

   
   

   ∴ S.I. for	5	yrs	= 55.20 ×	2	×	5	= ₹ 92
   	2			3		2

   
   ∴ Principal = Amount - SI = (1012 – 92) = ₹920
   

   ∴ Rate =		92 × 100
   	920 ×	5
   		2

   
   

   Rate =	2 × 92 × 100	= 4%
   	920 × 5

   
   Second method to solve this question :
   Here , A₂ = ₹ 1067.20 , T₁ = 5 /2 years , A₁ = ₹ 1012 , T₂ = 4 years
   

   R =		A1 - A2		× 100
   		A2T1 - A1T2

   
   

   Correct Option: C

   According to question ,
   

   Principal + S.I. for	5	yrs = ₹ 1012.............(i)
   	2

   
   Principal + S.I. for 4 years = 1067.20 ...(ii)
   Subtracting equation (i) from (ii)
   

   S.I. for	3	yrs = ₹ 55.20
   	2

   
   

   ∴ S.I. for	5	yrs	= 55.20 ×	2	×	5	= ₹ 92
   	2			3		2

   
   ∴ Principal = Amount - SI = (1012 – 92) = ₹920
   

   ∴ Rate =		92 × 100
   	920 ×	5
   		2

   
   

   Rate =	2 × 92 × 100	= 4%
   	920 × 5

   
   Second method to solve this question :
   Here , A₂ = ₹ 1067.20 , T₁ = 5 /2 years , A₁ = ₹ 1012 , T₂ = 4 years
   

   R =		A1 - A2		× 100
   		A2T1 - A1T2

   
   

   R =		1012 - 1067.20		× 100
   		1067.20 ×(5 ÷2) - 1012 × 4

   
   

   R =	- 55.2	× 100
   	(2668 - 4048)

   
   

   R =	- 55.2	× 100
   	- 1380

   
   R = 4%

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