Let the sum be P.
And the original rate be y% per annum.
Then new rate=(y+3)% per annum
According to question, [( P × ( y +3 ) × 2) / 100]=[(P × y × 2)/100]=300

Correct Option: A

Let the sum be P.
And the original rate be y% per annum.
Then new rate=(y+3)% per annum
According to question, [(P × (y+3) × 2)/100]=[(P × y × 2)/100]=300
∴ [(Py + 3P)/100]=[Py/100] = 150
∴ Py+ 3P - Py=15000
∴ 3P=15000
∴ P= 5000
Thus, the sum is Rs 5000

Let the sum be Rs 'y'
Since Simple Interest = Rs ( y / 2 )
So Simple Interest ,SI= (P x R x T)/100
where, R = Rate
T = Time
SI= Simple Interest

Correct Option: B

Let the sum be Rs 'y'
Since Simple Interest = Rs ( y / 2)
and, T = 6 yr , R = 10% per annum
So Simple Interest, SI = (P x R x T)/100
where, R = Rate
T = Time
SI= Simple Interest
now, According to problem, ( y / 2 ) = ( y x 10 x 6)/100
⇒ (1/2)=(6/10)
⇒ which is not true, so it is not a possible case.

As Sum = [( 100 x SI )/( Time x Rate)]

Correct Option: C

As Sum = [(100 x SI)/(Time x Rate)]
here, let R =x%, T=x yr, and, SI=Rs x
∴ Sum=[(100 × x)/(x × x)]
=(100/x)

Let the sum be Rs 'y' and , rate of interest = R%
Simple Interest for 2 yr =Rs( 625 - 575) = Rs 50

∴ R= [(100 x SI)/(Sum x Time)]

Correct Option: B

Let the sum be Rs 'y' and , rate of interest = R%
Simple Interest for 2 yr =Rs( 625 - 575 ) = Rs 50
∴ Sum of money, y=Rs( 575 - 75)= Rs 500

∴ R= [(100 x SI)/(Sum x Time)]
=[(100x 75)/(500 x 3)]=5 %

Let principle = Rs. P
Then S.I = P/9
Let Rate = R% per annum and time = R years

Then, as we know SI = (P x R x T) / 100.

Correct Option: C

Let principle = Rs. P
Then S.I = P/9
Let Rate = R% per annum and time = R years

Then, as we know SI = (P x R x T) / 100.
⇒ P/9 = ( P x R x R) / 100
⇒ R² = 100/9
∴ R = 10/3 = 3¹/₃ % per annum