Simple interest


  1. What sum of money must be given as simple interest for six months at 4% per annum in order to earn 150 interest?









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    As we know that ,

    P = Simple interest × 100
    Rate × Time

    Correct Option: B

    As we know that ,

    P = Simple interest × 100
    Rate × Time

    P = 150 × 100 × 2 = ₹ 7500
    41


  1. At some rate of simple interest, A lent 6,000 to B for 2 years and 1,500 to C for 4 years and received 9,00 as interest from both of them together. The rate of interest per annum was









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    Here , P1 = ₹ 6000 , P2 = ₹ 1500 , T1 = 2 years , T2 = 4 years and SI = ₹ 900
    If rate of interest be R% per annum then,

    SI =
    Principal × Time × Rate
    100

    Correct Option: A

    Here , P1 = ₹ 6000 , P2 = ₹ 1500 , T1 = 2 years , T2 = 4 years and SI = ₹ 900
    If rate of interest be R% per annum then,

    SI =
    Principal × Time × Rate
    100

    ∴ 900 =
    6000 × 2 × R
    +
    1500 × 4 × R
    100 100

    ⇒ 120R + 60R = 900
    ⇒ 180R = 900
    ⇒ R = 900 ÷ 180 = 5%



  1. What sum of money will amount to 520 in 5 years and to 568 in 7 years at simple interest ?









  1. View Hint View Answer Discuss in Forum

    Given that , A1 = ₹ 520 , A2 = ₹ 568 , T1 = 5 years , T2 = 7 years
    Simple interest for 2 years = ₹(568 – 520) = ₹ 48

    ∴ Interest for 5 years = ₹
    48
    × 5 = ₹ 120
    2

    Principal = Amount - Simple Interest = (520 – 120) = 400
    Second method to solve this question :
    Here , A2 = ₹ 568 , T1 = 5 years , A1 = ₹ 520 , T2 = 7 years
    P =
    A2T1 - A1T2
    T12

    P =
    568 × 5 - 520 × 7
    5 - 7

    Correct Option: A

    Given that , A1 = ₹ 520 , A2 = ₹ 568 , T1 = 5 years , T2 = 7 years
    Simple interest for 2 years = ₹(568 – 520) = ₹ 48

    ∴ Interest for 5 years = ₹
    48
    × 5 = ₹ 120
    2

    Principal = Amount - Simple Interest = (520 – 120) = 400
    Second method to solve this question :
    Here , A2 = ₹ 568 , T1 = 5 years , A1 = ₹ 520 , T2 = 7 years
    P =
    A2T1 - A1T2
    T12

    P =
    568 × 5 - 520 × 7
    5 - 7

    P =
    2840 - 3640
    - 2

    P = (- 800 ) ÷ ( -2 ) = ₹ 400


  1. A certain sum of money amounts to 756 in 2 years and to 873 in 31
    3
    years at a certain rate of simple interest. The rate of interest per annum is









  1. View Hint View Answer Discuss in Forum

    SI for 1
    1
    yrs = ₹(873 – 756) = ₹117
    2

    S.I. for 2 years = ₹117 ×
    2
    × 2 = ₹156
    3

    ∴ Principal = 756 – 156 = ₹600
    Now, P = ₹ 600, T = 2 years , S.I. = ₹ 156
    ∴ R =
    100 × S.I
    P × T

    R =
    100 × 156
    = 13%
    600 × 2

    Second method to solve this question :
    Here , A2 = ₹ 873 , T1 = 2 years , A1 = ₹ 756 , T2 = 3.5 years = 7 / 2 years
    Rate of interest =
    A1 - A2
    × 100
    A2T1 - A1T2

    Rate of interest =
    756 -873
    × 100
    873 ×2 - 756 ×
    7
    2

    Correct Option: D

    SI for 1
    1
    yrs = ₹(873 – 756) = ₹117
    2

    S.I. for 2 years = ₹117 ×
    2
    × 2 = ₹156
    3

    ∴ Principal = 756 – 156 = ₹600
    Now, P = ₹ 600, T = 2 years , S.I. = ₹ 156
    ∴ R =
    100 × S.I
    P × T

    R =
    100 × 156
    = 13%
    600 × 2

    Second method to solve this question :
    Here , A2 = ₹ 873 , T1 = 2 years , A1 = ₹ 756 , T2 = 3.5 years = 7 / 2 years
    Rate of interest =
    A1 - A2
    × 100
    A2T1 - A1T2

    Rate of interest =
    756 -873
    × 100
    873 ×2 - 756 ×
    7
    2

    Rate of interest =
    - 117
    × 100
    1746 - 2646

    Rate of interest =
    - 117
    × 100 = 13%
    - 900



  1. What sum will amount to 7000 in 5 years at 31% simple inter-
    est ?
    3










  1. View Hint View Answer Discuss in Forum

    Here , A = ₹ 7000 , T= 5 years , R =
    10
    3

    We find the required answer with the help of given formula ,
    P =
    A × 100
    100 + R × T

    Correct Option: C

    Here , A = ₹ 7000 , T= 5 years , R =
    10
    3

    We find the required answer with the help of given formula ,
    P =
    A × 100
    100 + R × T

    P =
    7000 × 100
    100 +
    10
    × 5
    3

    P =
    7000 × 100 × 3
    = ₹ 6000
    350