Simple interest
- What sum of money must be given as simple interest for six months at 4% per annum in order to earn 150 interest?
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As we know that ,
P = Simple interest × 100 Rate × Time
Correct Option: B
As we know that ,
P = Simple interest × 100 Rate × Time P = 150 × 100 × 2 = ₹ 7500 4 1
- At some rate of simple interest, A lent 6,000 to B for 2 years and 1,500 to C for 4 years and received 9,00 as interest from both of them together. The rate of interest per annum was
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Here , P1 = ₹ 6000 , P2 = ₹ 1500 , T1 = 2 years , T2 = 4 years and SI = ₹ 900
If rate of interest be R% per annum then,SI = Principal × Time × Rate 100
Correct Option: A
Here , P1 = ₹ 6000 , P2 = ₹ 1500 , T1 = 2 years , T2 = 4 years and SI = ₹ 900
If rate of interest be R% per annum then,SI = Principal × Time × Rate 100 ∴ 900 = 6000 × 2 × R + 1500 × 4 × R 100 100
⇒ 120R + 60R = 900
⇒ 180R = 900
⇒ R = 900 ÷ 180 = 5%
- What sum of money will amount to 520 in 5 years and to 568 in 7 years at simple interest ?
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Given that , A1 = ₹ 520 , A2 = ₹ 568 , T1 = 5 years , T2 = 7 years
Simple interest for 2 years = ₹(568 – 520) = ₹ 48∴ Interest for 5 years = ₹ 48 × 5 = ₹ 120 2
Principal = Amount - Simple Interest = (520 – 120) = 400
Second method to solve this question :
Here , A2 = ₹ 568 , T1 = 5 years , A1 = ₹ 520 , T2 = 7 yearsP = A2T1 - A1T2 T12 P = 568 × 5 - 520 × 7 5 - 7
Correct Option: A
Given that , A1 = ₹ 520 , A2 = ₹ 568 , T1 = 5 years , T2 = 7 years
Simple interest for 2 years = ₹(568 – 520) = ₹ 48∴ Interest for 5 years = ₹ 48 × 5 = ₹ 120 2
Principal = Amount - Simple Interest = (520 – 120) = 400
Second method to solve this question :
Here , A2 = ₹ 568 , T1 = 5 years , A1 = ₹ 520 , T2 = 7 yearsP = A2T1 - A1T2 T12 P = 568 × 5 - 520 × 7 5 - 7 P = 2840 - 3640 - 2
P = (- 800 ) ÷ ( -2 ) = ₹ 400
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years at a certain rate of simple interest. The rate of interest per annum isA certain sum of money amounts to 756 in 2 years and to 873 in 3 1 3
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SI for 1 1 yrs = ₹(873 – 756) = ₹117 2 S.I. for 2 years = ₹ 117 × 2 × 2 = ₹156 3
∴ Principal = 756 – 156 = ₹600
Now, P = ₹ 600, T = 2 years , S.I. = ₹ 156∴ R = 100 × S.I P × T R = 100 × 156 = 13% 600 × 2
Second method to solve this question :
Here , A2 = ₹ 873 , T1 = 2 years , A1 = ₹ 756 , T2 = 3.5 years = 7 / 2 yearsRate of interest = A1 - A2 × 100 A2T1 - A1T2 Rate of interest = 756 -873 × 100 873 ×2 - 756 × 7 2
Correct Option: D
SI for 1 1 yrs = ₹(873 – 756) = ₹117 2 S.I. for 2 years = ₹ 117 × 2 × 2 = ₹156 3
∴ Principal = 756 – 156 = ₹600
Now, P = ₹ 600, T = 2 years , S.I. = ₹ 156∴ R = 100 × S.I P × T R = 100 × 156 = 13% 600 × 2
Second method to solve this question :
Here , A2 = ₹ 873 , T1 = 2 years , A1 = ₹ 756 , T2 = 3.5 years = 7 / 2 yearsRate of interest = A1 - A2 × 100 A2T1 - A1T2 Rate of interest = 756 -873 × 100 873 ×2 - 756 × 7 2 Rate of interest = - 117 × 100 1746 - 2646 Rate of interest = - 117 × 100 = 13% - 900
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What sum will amount to 7000 in 5 years at 3 1 % simple inter-
est ?3
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Here , A = ₹ 7000 , T= 5 years , R = 10 3
We find the required answer with the help of given formula ,P = A × 100 100 + R × T
Correct Option: C
Here , A = ₹ 7000 , T= 5 years , R = 10 3
We find the required answer with the help of given formula ,P = A × 100 100 + R × T P = 7000 × 100 100 + 10 × 5 3 P = 7000 × 100 × 3 = ₹ 6000 350