26. A sum of Rs. 2800 is divided into two parts in such a way that the interest on both the parts is equal. If the first part is lent at 9% p.a. for 5 years and second part is for 6 years at 10% p.a., find the two sums.
    

1. 1. Rs. 1800, Rs. 1000
      

   
   
   

   2. Rs. 1600, Rs. 1200
      

   
   
   

   3. Rs. 1400, Rs. 1400
      

   
   
   

   4. Rs. 1300, Rs. 1500

   
   
   

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1. View Hint View Answer Discuss in Forum

   Let first part be y.
   ∴ Second part = Rs. (2800 – y)
   According to the question,
   

   SI =	Principal × Time × Rate
   	100

   
   

   ∴	y × 5 × 9	=	(2800 - y) × 6 × 10
   	100		100

   
   ⇒ 3y = 4 × 2800 – 4y
   ⇒ 7y = 4 × 2800
   

   Correct Option: B

   Let first part be y.
   ∴ Second part = Rs. (2800 – y)
   According to the question,
   

   SI =	Principal × Time × Rate
   	100

   
   

   ∴	y × 5 × 9	=	(2800 - y) × 6 × 10
   	100		100

   
   ⇒ 3y = 4 × 2800 – 4y
   ⇒ 7y = 4 × 2800
   

   ⇒ y =	4 × 2800	= Rs. 1600
   	7

   
   ∴ Second part = Rs. (2800 – 1600) = Rs. 1200

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27. The simple interest on a sum for 5 years is two-fifth of the sum. The rate of interest per annum is
    

1. 1. 0.1
      

   
   
   

   2. 0.08
      

   
   
   

   3. 0.06
      

   
   
   

   4. 0.04

   
   
   

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1. View Hint View Answer Discuss in Forum

   According to the question,
   

   SI	=	2
   Principal		5

   
   

   ∴ Rate =	SI × 100
   	Principal × Time

   
   

   Correct Option: B

   According to the question,
   

   SI	=	2
   Principal		5

   
   

   ∴ Rate =	SI × 100
   	Principal × Time

   
   

   Rate =	2	×	100	= 8% per annum
   	5		5

   
   Rate = 0.08 per annum

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28. If the simple interest on Re. 1 for 1 month is 1 paisa, then the rate percent per annum will be
    

1. 1. 10%
      

   
   
   

   2. 8%
      

   
   
   

   3. 12%
      

   
   
   

   4. 6%

   
   
   

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1. View Hint View Answer Discuss in Forum

   Given , Principle = ₹ 1 , Time = 1 month = ( 1 / 12 ) year and SI = 1 paisa = ₹ ( 1 / 100 )
   As we know that ,
   

   Rate =	SI × 100
   	Principal × Time

   
   

   Correct Option: C

   Given , Principle = ₹ 1 , Time = 1 month = ( 1 / 12 ) year and SI = 1 paisa = ₹ ( 1 / 100 )
   As we know that ,
   

   Rate =	SI × 100
   	Principal × Time

   
   

   Rate =	(1 ÷ 100) × 100	= 12% p.a.
   	1 × (1 ÷ 12)

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29. How much simple interest will Rs. 4000 earn in 18 months at 12% per annum?
    

1. 1. Rs. 216
      

   
   
   

   2. Rs. 360
      

   
   
   

   3. Rs. 720
      

   
   
   

   4. Rs. 960

   
   
   

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1. View Hint View Answer Discuss in Forum

   We find the required answer with the help of given formula ,
   

   SI =	Principal × Time × Rate
   	100

   
   

   SI =		4000 ×	18	×	12
   			12		100

   
   

   Correct Option: C

   We find the required answer with the help of given formula ,
   

   SI =	Principal × Time × Rate
   	100

   
   

   SI =		4000 ×	18	×	12
   			12		100

   
   SI = Rs. 720

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30. For what sum will the simple interest at R% per annum for 2 years will be R ?
    

1. 1. Rs.	100
      	2R

   
   
   

   2. Rs. 50

   
   
   

   3. Rs.	100
      	R

   
   
   

   4. Rs.	200
      	R

   
   
   

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1. View Hint View Answer Discuss in Forum

   Given that , SI = R , Rate = R% and Time = 2 years
   As we know that ,
   

   Principal =	SI × 100
   	Time × Rate

   
   

   Principal =	R × 100
   	2 × R

   
   

   Correct Option: B

   Given that , SI = R , Rate = R% and Time = 2 years
   As we know that ,
   

   Principal =	SI × 100
   	Time × Rate

   
   

   Principal =	R × 100
   	2 × R

   
   Principal = Rs. 50

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