131. A 100 km long transmission line is loaded at 110 kV. If the loss of line is 5 MW and the load is 150 MVA, the resistance of the line is

1. 1. 8.06 ohms per phase

   
   
   

   2. 0.806 ohms per phase

   
   
   

   3. 0.0806 ohms per phase

   
   
   

   4. 80.6 ohms per phase

   
   
   

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1. View Hint View Answer Discuss in Forum

   PL = I²_LR
   Here,
   

   I²L =	150 × 106	=	150	× 10³
   	110 × 10³		110

   
   

   ∴ 15 × 106 =		150		²	× 106 × R
   		110

   
   or R = 8.06 ohms/phase

   Correct Option: A

   PL = I²_LR
   Here,
   

   I²L =	150 × 106	=	150	× 10³
   	110 × 10³		110

   
   

   ∴ 15 × 106 =		150		²	× 106 × R
   		110

   
   or R = 8.06 ohms/phase

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132. For a single phase overhead line having solid copper conductors of diameter 1 cm, spaced 60 cm between centers, the inductance in mH/km is

1. 1. 0.05 + 0.2 ln 60

   
   
   

   2. 0.2 ln 60

   
   
   

   3. 0.05 + 0.2 ln (60/0.5)

   
   
   

   4. 0.2 ln (60/0.5)

   
   
   

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1. View Hint View Answer Discuss in Forum

   NA

   Correct Option: C

   NA

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133. In a DC transmission line

1. 1. it is necessary for the sending end and receiving end to be operated in synchronism

   
   
   

   2. the effects of inductive and capacitive reactances are greater than in an AC transmission line of the same rating.

   
   
   

   3. there are no effects due to inductive and capacitive reactances.

   
   
   

   4. power transfer capability is limited by stability considerations.

   
   
   

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1. View Hint View Answer Discuss in Forum

   NA

   Correct Option: C

   NA

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134. In the above question, the maximum energy that could be produced daily is

1. 1. 500 MWh/day

   
   
   

   2. 360 MWh/day

   
   
   

   3. 600 MWh/day

   
   
   

   4. 720 MWh/day

   
   
   

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1. View Hint View Answer Discuss in Forum

   Load factor =	Average demand
   	Maximum demand

   
   Average demand = 0.60 × 25 = 15 MW
   Daily energy produced = Average demand × 24 = (15 × 24) = 360 MWh
   

   Maximum energy that could be produced =	Actual energy produced in a day
   	Plant use factor

   
   

   =	30	= 500 mwh/day
   	0.72

   Correct Option: A

   Load factor =	Average demand
   	Maximum demand

   
   Average demand = 0.60 × 25 = 15 MW
   Daily energy produced = Average demand × 24 = (15 × 24) = 360 MWh
   

   Maximum energy that could be produced =	Actual energy produced in a day
   	Plant use factor

   
   

   =	30	= 500 mwh/day
   	0.72

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135. A generating station has a maximum demand of 20 mW, load factor of 60%, a plant capacity factor of 50% and a plant use factor of 72%. What is the reserve capacity of the plant, if the plant, while running as per schedule, were fully loaded?

1. 1. 10 MW

   
   
   

   2. 15 MW

   
   
   

   3. 2 MW

   
   
   

   4. 5 MW

   
   
   

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1. View Hint View Answer Discuss in Forum

   Load factor =	Average demand
   	Maximum demand

   
   

   or 0.60 =	Average demand
   	25

   
   ∴ Average demand = 25 × 0.60 = 15 MW
   

   Plant capacity factor =	Average demand
   	Installed capacity

   
   

   or 0.50 =	15
   	Installed capacity

   
   

   ∴ Installed capacity =	15	= 30 MW
   	0.50

   
   Reserve capacity of the plant = Installed capacity – Maximum demand = (30 – 25) = 5 MW

   Correct Option: D

   Load factor =	Average demand
   	Maximum demand

   
   

   or 0.60 =	Average demand
   	25

   
   ∴ Average demand = 25 × 0.60 = 15 MW
   

   Plant capacity factor =	Average demand
   	Installed capacity

   
   

   or 0.50 =	15
   	Installed capacity

   
   

   ∴ Installed capacity =	15	= 30 MW
   	0.50

   
   Reserve capacity of the plant = Installed capacity – Maximum demand = (30 – 25) = 5 MW

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