Power systems miscellaneous


  1. The voltage of generator and an infinite bus are given as 0.92 ∠10° and 1.0∠0° respectively. The generator acts as a









  1. View Hint View Answer Discuss in Forum

    NA

    Correct Option: A

    NA


  1. It x is the system reactance and r is its resistance, the power transferred is maximum when









  1. View Hint View Answer Discuss in Forum


    I =
    V1∠δ - V2∠0
    Z∠θ

    =
    V1
    ∠(δ - ∠0) -
    V2
    ∠- θ
    ZZ

    Power received, P2 = Re [V2I*]
    = ReV2
    V1
    ∠(θ - δ) -
    V2
    ∠θ
    ZZ

    =
    V1V2
    cos(θ - δ) -
    2
    cos θ
    ZZ

    Let θ = 90° – α, then
    =
    V1V2
    cos(90° - α - δ) -
    2
    cos(90° - α)
    ZZ

    =
    V1V2
    sin(α + δ) -
    2
    sin α
    ZZ

    P2 max =
    V1V2
    -
    2
    sin α[α + δ = 90°]
    ZZ

    As, sin α =
    r
    , then
    Z

    P2 max =
    V1V2
    -
    2
    .
    r
    r² + x²r² + x²r² + x²

    For P2 max to be maximum,
    dP2 max
    = 0
    dx

    or V²2
    x1
    -
    2xr
    = 0
    (r² + x²)2/3(r² + x²)²

    Here V1 = V2
    ∴ r² + x² = 4r²
    or x = 3r

    Correct Option: C


    I =
    V1∠δ - V2∠0
    Z∠θ

    =
    V1
    ∠(δ - ∠0) -
    V2
    ∠- θ
    ZZ

    Power received, P2 = Re [V2I*]
    = ReV2
    V1
    ∠(θ - δ) -
    V2
    ∠θ
    ZZ

    =
    V1V2
    cos(θ - δ) -
    2
    cos θ
    ZZ

    Let θ = 90° – α, then
    =
    V1V2
    cos(90° - α - δ) -
    2
    cos(90° - α)
    ZZ

    =
    V1V2
    sin(α + δ) -
    2
    sin α
    ZZ

    P2 max =
    V1V2
    -
    2
    sin α[α + δ = 90°]
    ZZ

    As, sin α =
    r
    , then
    Z

    P2 max =
    V1V2
    -
    2
    .
    r
    r² + x²r² + x²r² + x²

    For P2 max to be maximum,
    dP2 max
    = 0
    dx

    or V²2
    x1
    -
    2xr
    = 0
    (r² + x²)2/3(r² + x²)²

    Here V1 = V2
    ∴ r² + x² = 4r²
    or x = 3r



  1. A motor is receiving 25% of the power that it is capable of receiving from an infinite bus. If load of the motor is doubled, then maximum value of δ during swinging of the rotor ar ound it s new equilibrium position will be









  1. View Hint View Answer Discuss in Forum


    sin δ0 = 0.25,
    ⇒ δ0 = 14.48°
    sin δc = 0.5,
    ⇒ δ0 = 30°

    or 0.5 (δm – 0.2527) = (cos δ0 – cos δm)
    or 0.5 δm = cos δ0 – cos δm + 0.1263
    For solution of this we make guess for δm such that δm should be greater than 30° (as δc = 30°).
    After some trials, δm is found to be 45°.

    Correct Option: B


    sin δ0 = 0.25,
    ⇒ δ0 = 14.48°
    sin δc = 0.5,
    ⇒ δ0 = 30°

    or 0.5 (δm – 0.2527) = (cos δ0 – cos δm)
    or 0.5 δm = cos δ0 – cos δm + 0.1263
    For solution of this we make guess for δm such that δm should be greater than 30° (as δc = 30°).
    After some trials, δm is found to be 45°.


  1. An ideal voltage source is connected across a variable resistance. The variation of current as a function of resistance is given by









  1. View Hint View Answer Discuss in Forum

    NA

    Correct Option: B

    NA



  1. In a synchronous machine, in case the axis of field flux is in line with the armature flux, the machine is working









  1. View Hint View Answer Discuss in Forum

    NA

    Correct Option: C

    NA