Power systems miscellaneous


  1. Buses for load flow studies are classified as (i) the load bus (ii) the generator bus (iii) the slace bus The correct combination of the pair of quantities specified having their usual meaning for different buses is
    Load Bus Generator Slace bus









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    Load bus = P, Q
    Generator bus = P, |V|
    Slack bus = |V|, δ

    Correct Option: B

    Load bus = P, Q
    Generator bus = P, |V|
    Slack bus = |V|, δ


  1. A power system network consists of three elements 0 - 1, 1 - 2 and 2 - 0 of per unit impedance 0.2, 0.4 respectively. Its bus impedance matrix is given by









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    The Bus impedance matrix ZBUS can be formed by using circuit theory knowledge

    Correct Option: B

    The Bus impedance matrix ZBUS can be formed by using circuit theory knowledge



  1. In a synchronous machine, in case the axis of field flux is in line with the armature flux, the machine is working









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    NA

    Correct Option: C

    NA


  1. It x is the system reactance and r is its resistance, the power transferred is maximum when









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    I =
    V1∠δ - V2∠0
    Z∠θ

    =
    V1
    ∠(δ - ∠0) -
    V2
    ∠- θ
    ZZ

    Power received, P2 = Re [V2I*]
    = ReV2
    V1
    ∠(θ - δ) -
    V2
    ∠θ
    ZZ

    =
    V1V2
    cos(θ - δ) -
    2
    cos θ
    ZZ

    Let θ = 90° – α, then
    =
    V1V2
    cos(90° - α - δ) -
    2
    cos(90° - α)
    ZZ

    =
    V1V2
    sin(α + δ) -
    2
    sin α
    ZZ

    P2 max =
    V1V2
    -
    2
    sin α[α + δ = 90°]
    ZZ

    As, sin α =
    r
    , then
    Z

    P2 max =
    V1V2
    -
    2
    .
    r
    r² + x²r² + x²r² + x²

    For P2 max to be maximum,
    dP2 max
    = 0
    dx

    or V²2
    x1
    -
    2xr
    = 0
    (r² + x²)2/3(r² + x²)²

    Here V1 = V2
    ∴ r² + x² = 4r²
    or x = 3r

    Correct Option: C


    I =
    V1∠δ - V2∠0
    Z∠θ

    =
    V1
    ∠(δ - ∠0) -
    V2
    ∠- θ
    ZZ

    Power received, P2 = Re [V2I*]
    = ReV2
    V1
    ∠(θ - δ) -
    V2
    ∠θ
    ZZ

    =
    V1V2
    cos(θ - δ) -
    2
    cos θ
    ZZ

    Let θ = 90° – α, then
    =
    V1V2
    cos(90° - α - δ) -
    2
    cos(90° - α)
    ZZ

    =
    V1V2
    sin(α + δ) -
    2
    sin α
    ZZ

    P2 max =
    V1V2
    -
    2
    sin α[α + δ = 90°]
    ZZ

    As, sin α =
    r
    , then
    Z

    P2 max =
    V1V2
    -
    2
    .
    r
    r² + x²r² + x²r² + x²

    For P2 max to be maximum,
    dP2 max
    = 0
    dx

    or V²2
    x1
    -
    2xr
    = 0
    (r² + x²)2/3(r² + x²)²

    Here V1 = V2
    ∴ r² + x² = 4r²
    or x = 3r



  1. The voltage of generator and an infinite bus are given as 0.92 ∠10° and 1.0∠0° respectively. The generator acts as a









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    NA

    Correct Option: A

    NA