Fluid Mechanics and Hydraulic Machinery Miscellaneous
- For a steady flow, the velocity field is V = (–x² + 3y) i + (2xy)j. The magnitude of the acceleration of a particle at (1, - 1) is
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NA
Correct Option: C
NA
- For a two-dimensional flow, the velocity field is
u = x i + y j x² + y² x² + y²
where i and j are the basis vectors in the x – y Cartesian coordinate system. Identify the CORRECT statements from below.
1. The flow is incompressible
2. The flow is unsteady
3. y-component of acceleration,ay = - y (x² + y²)²
4. x-component of acceleration,ax = -(x + y) (x² + y²)²
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axu δu + v δu δx δy = x(x² + y² -2x²)-2xy² = - x3 - xy² (x² + y²)(x² + y²) (x² + y²) ∴ ax = x (x² + y²)² ay = u δv + v δv δx δy = -x² + yx² - y3 = - y (x² + y²)3 (x² + y²)²
The velocity components are not functions of time, so flow is steady according to continuity equation,
Since it satisfies the above continuity equation for 2D and incompressible flow.
∴ The flow is incompressible.Correct Option: B
axu δu + v δu δx δy = x(x² + y² -2x²)-2xy² = - x3 - xy² (x² + y²)(x² + y²) (x² + y²) ∴ ax = x (x² + y²)² ay = u δv + v δv δx δy = -x² + yx² - y3 = - y (x² + y²)3 (x² + y²)²
The velocity components are not functions of time, so flow is steady according to continuity equation,
Since it satisfies the above continuity equation for 2D and incompressible flow.
∴ The flow is incompressible.
- For a certain two-dimensional incompressible flow, velocity field is given by 2xyi – y² j. The streamlines for this flow are given by the family of curves
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v = 2xy i – y²j
u = δx , v = - δx δy δx 2xy = δx = 2 δy
2xyδy = δψ
on integrating
ψ = xy² + f(x)
= y1 + f'(x)
f'(x) = 0
⇒ f(x)= constant
so ψ= xy² + constantCorrect Option: B
v = 2xy i – y²j
u = δx , v = - δx δy δx 2xy = δx = 2 δy
2xyδy = δψ
on integrating
ψ = xy² + f(x)
= y1 + f'(x)
f'(x) = 0
⇒ f(x)= constant
so ψ= xy² + constant
- The volumetric flow rate (per unit depth) between two streamlines having stream function ψ1 and ψ2 is
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NA
Correct Option: D
NA
- The velocity field of an incompressible flow is given by V = (a1x + a2y + a3 z)i + (b1x + b2y + b3 z)j + (c1x + c2y + c3 z)k, where a1 = 2 and c3 = –4. The value of b2 is _________.
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δu + δv + δw = 0 δx δy δz
a1 + b2 + c3 = 0
2 – 4 + b2 = 0
b2 = 2
Correct Option: A
δu + δv + δw = 0 δx δy δz
a1 + b2 + c3 = 0
2 – 4 + b2 = 0
b2 = 2