Fluid Mechanics and Hydraulic Machinery Miscellaneous
- For a certain two-dimensional incompressible flow, velocity field is given by 2xyi – y² j. The streamlines for this flow are given by the family of curves
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v = 2xy i – y²j
u = δx , v = - δx δy δx 2xy = δx = 2 δy
2xyδy = δψ
on integrating
ψ = xy² + f(x)
= y1 + f'(x)
f'(x) = 0
⇒ f(x)= constant
so ψ= xy² + constantCorrect Option: B
v = 2xy i – y²j
u = δx , v = - δx δy δx 2xy = δx = 2 δy
2xyδy = δψ
on integrating
ψ = xy² + f(x)
= y1 + f'(x)
f'(x) = 0
⇒ f(x)= constant
so ψ= xy² + constant
- The volumetric flow rate (per unit depth) between two streamlines having stream function ψ1 and ψ2 is
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NA
Correct Option: D
NA
- The velocity field of an incompressible flow is given by V = (a1x + a2y + a3 z)i + (b1x + b2y + b3 z)j + (c1x + c2y + c3 z)k, where a1 = 2 and c3 = –4. The value of b2 is _________.
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δu + δv + δw = 0 δx δy δz
a1 + b2 + c3 = 0
2 – 4 + b2 = 0
b2 = 2
Correct Option: A
δu + δv + δw = 0 δx δy δz
a1 + b2 + c3 = 0
2 – 4 + b2 = 0
b2 = 2
- If the fluid velocity for a potential flow is given by V(x, y) = u(x, y)i + v(x, y)j with usual notations, then the slope of the potential line at (x, y) is
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Here V(x, y) = u(x, y) i + v(x, y) j
As we know that u = -δφ δx ∴ -δφ = -v(x,y) ....(i) δx Similarly v = -δφ δy ∴ -δφ = -v(x,y) ....(ii) δy
From equations (i) and (ii) we get,
Correct Option: B
Here V(x, y) = u(x, y) i + v(x, y) j
As we know that u = -δφ δx ∴ -δφ = -v(x,y) ....(i) δx Similarly v = -δφ δy ∴ -δφ = -v(x,y) ....(ii) δy
From equations (i) and (ii) we get,
- Consider a velocity field V K(yi + xk), where K is a constant. The vorticity, Ω Z, is
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NA
Correct Option: A
NA