Direction: The gap between a moving circular plate and a stationary surface is being continuously reduced, as the circular plate comes down at a uniform speed V towards the stationary bottom surface, as shown in the figure. In the process, the fluid contained between the two plates flows out radially. The fluid is assumed to be incompressible and inviscid.
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The radial component of the fluid acceleration at r = R is
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3V2R 4h2
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V2R 4h2
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V2R 2h2
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V2h 2R2
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Correct Option: A
Radial acceleration
ar = Vr × | + | ||
∂r | ∂t |
ar = | × | ![]() | ![]() | + | ![]() | ![]() | |||||
2h | ∂r | 2h | ∂t | 2h |
= V | |
∂t |
∴ ar = | × | + | × | ![]() | ![]() | |||||
2h | 2h | 2 | h2 | ∂t |
∴ ar = | + | |||
4h2 | 4h2 |
ar = | ||
4h2 |