Average
- The average of 25 results is 18; that of first twelve is 14 and of last twelve is 17. Find the thirteenth result.
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The average of 25 results =18;
Sum of 25 results = Average × their number
Sum of 25 results = 18 × 25 = 450
The average of first twelve = 14
Similarly, Sum of 1st twelve results = 12 × 14 = 168
and The average of last twelve = 17Correct Option: B
The average of 25 results =18;
Sum of 25 results = Average × their number
Sum of 25 results = 18 × 25 = 450
The average of first twelve = 14
Similarly, Sum of 1st twelve results = 12 × 14 = 168
and The average of last twelve = 17
and sum of last twelve results = 12 × 17 = 204
∴ Thirteenth result = 450 – 168 – 204 = 78
- The average height of 30 girls out of a class of 40 is 160 cms and that of the remaining girls is 156 cms. What is the average height of the whole class?
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As per the given in question ,
Total height of the whole class = (30 × 160) + (40 – 30) × 156 = 6360 cmsCorrect Option: C
As per the given in question ,
Total height of the whole class = (30 × 160) + (40 – 30) × 156 = 6360 cms
Average height of the whole class = 6360 ÷ 40 = 159 cms.
- a, b, c, d and e are five consecutive odd numbers. What is their average?
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According to question ,
Each successive odd number exceeds its predecessor by 2.
a + b + c + d + e = a + (a + 2) + (a + 4) + (a + 6) + (a + 8) = 5a + 20 = 5 (a + 4)Average age = 5(a + 4) 5 Correct Option: B
According to question ,
Each successive odd number exceeds its predecessor by 2.
a + b + c + d + e = a + (a + 2) + (a + 4) + (a + 6) + (a + 8) = 5a + 20 = 5 (a + 4)Average age = 5(a + 4) = a + 4 5
- The average age of three boys is 15 years. If their ages are in the ratio 3 : 5 : 7, what is the age of the youngest boy?
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Let the age of three boys be 3k, 5k and 7k
According to question ,Average age = 3k + 5k + 7k = 5k 3
Correct Option: A
Let the age of three boys be 3k, 5k and 7k
According to question ,Average age = 3k + 5k + 7k = 5k 3
and, 5k = 15 ⇒ k = 3 years
The age of the youngest boy = 3k = 9 years.
- Out of three numbers, the first is twice of the second and is half of the third. If the average of three numbers is 56, find the largest number.
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Let the first number be y.
Second number = y / 2
Third number = 2yAverage = y + (y/2) + 2y = 7 y 3 6
Correct Option: C
Let the first number be y.
Second number = y / 2
Third number = 2yAverage = y + (y/2) + 2y = 7 y 3 6 Given : 7 y = 56 ⇒ y = 48 6
So, the three numbers are 48, 24 and 96.