Average
- A batsman in his 12th innings makes a score of 120, and thereby increases his average by 5. The average score after 12th innings is
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Given that , A batsman in his 12th innings makes a score = 120
and his average increases by = 5
Let Average runs after 12 innings = n
Average runs after 11 innings = n – 5
According to the question,
⇒ 12n = (n – 5) × 11 + 120Correct Option: C
Given that , A batsman in his 12th innings makes a score = 120
and his average increases by = 5
Let Average runs after 12 innings = n
Average runs after 11 innings = n – 5
According to the question,
⇒ 12n = (n – 5) × 11 + 120
⇒ 12n – 11n = 120 – 55
⇒ n = 65
- The average of runs of a cricket player of 20 innings was 32. How many runs must he make in his next innings so as to increase his average of runs by 4?
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Total runs scored by the cricketer in 20 innings = 32 × 20 = 640
If the runs scored in 21st innings be n , then
According to question ,
⇒ 640 + n = 21 × 36Correct Option: A
Total runs scored by the cricketer in 20 innings = 32 × 20 = 640
If the runs scored in 21st innings be n , then
According to question ,
⇒ 640 + n = 21 × 36
⇒ 640 + n = 756
⇒ n = 756 – 640 = 116
- A batsman makes a score of 87 runs in the 17th innings and thus increased his average by 3. Find his average after 17th innings.
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Here , A batsman makes a scored in the 17th innings = 87 runs
and increased by his average = 3
Average runs in 16 innings = 87 – 17 × 3 = 87 – 51 = 36Correct Option: A
Here , A batsman makes a scored in the 17th innings = 87 runs
and increased by his average = 3
Average runs in 16 innings = 87 – 17 × 3 = 87 – 51 = 36
∴ Required average = 36 + 3 = 39 runs
- Sachin Tendulkar has a certain average for 11 innings. In the 12th innings he scores 120 runs and thereby increases his average by 5 runs. His new average is
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Let Sachin’s new average = n runs
∴ Total runs in 11 innings = 11 (n – 5)
According to question ,
⇒ 11 (n – 5) + 120 = 12nCorrect Option: C
Let Sachin’s new average = n runs
∴ Total runs in 11 innings = 11 (n – 5)
According to question ,
⇒ 11 (n – 5) + 120 = 12n
⇒ 12n – 11n = 65
⇒ n = 65 runs
- The batting average for 30 inings of a cricket player is 40 runs. His highest score exceeds his lowest score by 100 runs. If these two innings are not included, the average of the remaining 28 innings is 38 runs. The lowest score of the player is :
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Let Lowest score = p
∴ Highest score = p + 100
According to question ,
⇒ 28 × 38 + p + p + 100 = 30 × 40
⇒ 1064 + 2p + 100 = 1200Correct Option: B
Let Lowest score = p
∴ Highest score = p + 100
According to question ,
⇒ 28 × 38 + p + p + 100 = 30 × 40
⇒ 1064 + 2p + 100 = 1200
⇒ 2p = 1200 – 1164 = 36
⇒ p = 18