Given
M + T + W + TH = 4 x 38° = 152°
T + W + TH + F = 4 x 40° = 160°
M = 30°

Correct Option: C

From question
M + T + W + TH = 4 x 38° = 152°
⇒ T + W + TH =152° – 30° = 122°

Again from question
⇒ T + W + TH + F = 4 x 40° = 160°
⇒ F = 160° – 122°
= 38°

Sum of 5 consecutive integers
x + ( x +1 ) + ( x +2 ) + ( x + 3 ) + ( x +4 ) = 5n
⇒ 5x + 10 = 5n
⇒ x = ( n – 2 ) ......(i)

Average of 7 consecutive integers
= [( 5x + 10 ) + ( x + 5 ) + ( x + 6 )] / 7
= 7x + 21 / 7
= x + 3 .....(ii)

Correct Option: B

Sum of 5 consecutive integers
x + ( x +1 ) + ( x +2 ) + ( x + 3 ) + ( x +4 ) = 5n
⇒ 5x + 10 = 5n
⇒ x = ( n – 2 ) ......(i)

Average of 7 consecutive integers
= [( 5x + 10 ) + ( x + 5 ) + ( x + 6 )] / 7
= 7x + 21 / 7
= x + 3 .....(ii)

from eq. (i) and (ii)
New average = x + 3 = ( n – 2 + 3 ) = n + 1
So , the new average increases by 1 .

Let the number of wickets taken before the last match = y
Bowler's overall average = total run scored / total wicket taken by bowler
Then, (12.4y + 26 ) / (y + 5) = 12

Correct Option: A

Let the number of wickets taken before the last match = y
Bowler's overall average = total run scored / total wicket taken by bowler
Then, (12.4y + 26 ) / (y + 5) = 12
∴ x = 85

Let the original expenditure be Rs. y per day ,
Then, y / 35 - [( y + 42 ) / 42 ] = 1

Correct Option: B

Let the original expenditure be Rs. y per day ,
Then, y / 35 - [( y + 42 ) / 42 ] = 1
⇒ 42y - 35 ( y + 42 ) = 35 x 42
∴ 7y = 35 x 42 + 35 x 42
⇒ y = ( 2 x 35 x 42 ) / 7
= 420
Hence , the original expenditure is Rs . 420

Age of child = sum of age of husband , wife and child - sum of age of husband and wife.
= [(20 x 3) - (23 x 2 + 5 x 2)] years

Correct Option: D

Age of child = sum of age of husband , wife and child - sum of age of husband and wife.
= [(20 x 3) - (23 x 2 + 5 x 2)] years
= 4 years.