Average
- The average weight of 10 parcels is 1.7 kg. Addition of another new parcel reduces the average weight by 60 gram. What is the weight in kg. of the new parcel?
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Here , The average weight of 10 parcels = 1.7 kg
Now , Weight of new parcel = 1.7 kg. – Total decreaseWeight of new parcel = 1.7 - 60 × 11 kg. 1000
Correct Option: A
Here , The average weight of 10 parcels = 1.7 kg
Now , Weight of new parcel = 1.7 kg. – Total decreaseWeight of new parcel = 1.7 - 60 × 11 kg. 1000
Weight of new parcel = (1.7 - 0.66) kg.
Weight of new parcel = 1.04 kg.
- The average (arithmetic mean) amount of savings of ten students is Rs. 600. Three of the students have no savings at all and each of the others have at least Rs. 250 including Nihar, who has exactly Rs. 1300. The largest amount, in Rs., that any one student could have saved is
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Here , The average amount of savings of ten students = Rs. 600
Total savings by 10 students = Rs. (10 × 600) = Rs. 6000
Three of the students have no savings.
Total savings by 6 students = Rs. (6000 – 1300) = Rs. 4700
Let the savings by each of 5 students be Rs. 250.Correct Option: B
Here , The average amount of savings of ten students = Rs. 600
Total savings by 10 students = Rs. (10 × 600) = Rs. 6000
Three of the students have no savings.
Total savings by 6 students = Rs. (6000 – 1300) = Rs. 4700
Let the savings by each of 5 students be Rs. 250.
∴ Largest amount of savings = Rs. (4700 – 5 × 250)
∴ Largest amount of savings = Rs. (4700 – 1250) = Rs. 3450
- Eight members of a club donate Rs. 100 each towards a Relief Fund and the President of the club donates Rs. 50 more than the average donation of all (including President) of them. Then the contribution of the president is
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Let the contribution of president be Rs. p.
According to the question,⇒ p – p + 800 = 50 9 ⇒ 9p - p - 800 = 50 9
⇒ 8p – 800 = 50 × 9
Correct Option: B
Let the contribution of president be Rs. p.
According to the question,⇒ p – p + 800 = 50 9 ⇒ 9p - p - 800 = 50 9
⇒ 8p – 800 = 50 × 9
⇒ 8p = 450 + 800 = 1250
⇒ p = 1250 ÷ 8 = Rs. 156.25
- On 24th May, 2008 the maximum temperature of Delhi, Kolkata and Mumbai were recorded as 35°C, 33°C and 34°C respectively. What was the maximum temperature of Chennai so that the average maximum temperature of those cities would be 35°?
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Let the maximum temperature of Chennai be t°C.
According to the question,⇒ 35° + 33° + 34° + t° = 35° 4
Correct Option: D
Let the maximum temperature of Chennai be t°C.
According to the question,⇒ 35° + 33° + 34° + t° = 35° 4
⇒ 102° + t° = (35 × 4)° = 140°
⇒ t° = 140° – 102° = 38°C
- Last year, 5 companies had an average of 16 non working days each. This year, 3 companies had 10 more non working days each, and 2 companies had 5 fewer non working days each. What was the average number of non working days given by the same companies this year ?
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Here , The average of 5 companies non working days = 16
Number of non-working days last year = 5 × 16 = 80
According to question ,
Number of non-working days this year = 80 + 3 × 10 – 2 × 5 = 100Correct Option: C
Here , The average of 5 companies non working days = 16
Number of non-working days last year = 5 × 16 = 80
According to question ,
Number of non-working days this year = 80 + 3 × 10 – 2 × 5 = 100
∴ Required average = 100 &divivde; 5 = 20