Out of three numbers, the first is twice of the second and

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Out of three numbers, the first is twice of the second and is half of the third. If the average of three numbers is 56, find the largest number.

1. 50
2. 48
3. 96
4. 75

Correct Option: C

Let the first number be y.
Second number = y / 2
Third number = 2y

Average =	y + (y/2) + 2y	=	7	y
	3		6

Given :	7	y = 56 ⇒ y = 48
	6

So, the three numbers are 48, 24 and 96.