Signal and systems miscellaneous
- Double integration of unit step function would lead to—
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First integration of
u(t) = tu(t).
Second integration ofu(t) = t2 u(t) 2
which represent parabola form.
Hence, alternative (B) is correct answer.Correct Option: B
First integration of
u(t) = tu(t).
Second integration ofu(t) = t2 u(t) 2
which represent parabola form.
Hence, alternative (B) is correct answer.
- A Matched filter has a frequency response is given by
H(f) = 1 – e– j2πfT , j2πf
the impulse response h(t) of the filter will be—
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Given that
H(f) = 1 – e-j2πft j2πf or H(f) = 1 – e-j2πfT j2πf j2πf or H(f) = 1 – e-jωT jω jω
We know that
sgn t ←f(jω)→ 2 jω
sgn (t – T) ←f(jω)→2 jω⎯⎯ e– jωT
Therefore, the impulse response can be obtained by taking inverse Laplace transform i.e.,h(t)=L– 1 1 – 1 · e– jωT jω jω or h(t) = sgn t – sgn (t – T) 2 2
Hence, alternative (A) is the correct choice.Correct Option: A
Given that
H(f) = 1 – e-j2πft j2πf or H(f) = 1 – e-j2πfT j2πf j2πf or H(f) = 1 – e-jωT jω jω
We know that
sgn t ←f(jω)→ 2 jω
sgn (t – T) ←f(jω)→2 jω⎯⎯ e– jωT
Therefore, the impulse response can be obtained by taking inverse Laplace transform i.e.,h(t)=L– 1 1 – 1 · e– jωT jω jω or h(t) = sgn t – sgn (t – T) 2 2
Hence, alternative (A) is the correct choice.
- Fourier terms form F(jω) of an arbitrary signal has the property—
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NA
Correct Option: B
NA
- The inverse Fourier transform of the function
F(ω) = 1 + πδ(ω) is— jω
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Since, Fourier transform of unit step function is
1 + πs(ω) so, inverse Fourier transform will be u(t). jω
Hence, alternative (D) is the correct choice.Correct Option: D
Since, Fourier transform of unit step function is
1 + πs(ω) so, inverse Fourier transform will be u(t). jω
Hence, alternative (D) is the correct choice.
- The amplitude spectrum of a Gaussian pulse is—
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NA
Correct Option: C
NA