Signal and systems miscellaneous
- The unit sample response of a discrete system is 1 1/2 1/4 0 0 0 … For an input sequence 1 0 10 0 0 … what is the output sequence?
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Given that,
h[n] = 1 1 1 0 0 0 ............ 2 4
x[n] = 1 0 1 0 0 0 ……
y(n) can be calculated by using method given below:y[n] = 1 1 1 + 1 1 1 0 0 ............ 2 4 2 4
ory[n] = 1 1 5 1 1 0 0 ............ 2 4 2 4
Hence, alternative (D) is the correct choice.Correct Option: D
Given that,
h[n] = 1 1 1 0 0 0 ............ 2 4
x[n] = 1 0 1 0 0 0 ……
y(n) can be calculated by using method given below:y[n] = 1 1 1 + 1 1 1 0 0 ............ 2 4 2 4
ory[n] = 1 1 5 1 1 0 0 ............ 2 4 2 4
Hence, alternative (D) is the correct choice.
- Consider the following statements about linear time invariant (LTI) continuous time systems:
1. The output signal in an LTI system with known input and known impulse response can always be determined.
2. A causal LTI system is always stable.
3. A causal LTI system has an impulse response. h(t) which has a finite value when integrated h(t) overwhole of the time axis, i.e., + ∞ is finite. – ∞
Which of the statements given above are correct?
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Since, it is not necessary true that causal system is always stable.
Hence, alternative (D) is the correct choice.Correct Option: D
Since, it is not necessary true that causal system is always stable.
Hence, alternative (D) is the correct choice.
- In the graph shown below, which one of the following expresses v(t)?
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Slope of the given wave = 2/1
Equation of triangular wave which cuts at point-6 on the y axis is r(t) = (2t – 6) u(t)
Therefore, the expression of v(t) can be expressed as
v(t) = (2t – 6) u(t – 3) – (2t – 6) u(t – 4)
or
v(t) = (2t – 6) [u(t – 3) – u(t – 4)]Correct Option: D
Slope of the given wave = 2/1
Equation of triangular wave which cuts at point-6 on the y axis is r(t) = (2t – 6) u(t)
Therefore, the expression of v(t) can be expressed as
v(t) = (2t – 6) u(t – 3) – (2t – 6) u(t – 4)
or
v(t) = (2t – 6) [u(t – 3) – u(t – 4)]
- The governing differential equations connecting the output y(t) and the input x (t) of four continuous time systems are given in the List-I and List-II respectively. Match List-I (Equation) with List-II (System Category) and select the correct answer using the code given below the Lists—
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(A) 2t dy + 4y = 2tx dt
● Since, there is no constant hence linear.
● t factor means time-variant.
● dy/dt term means dynamic which gives A → 3
(B) y dy + 4y = 2x dt
● Since, there is no constant term mean linear
● No time varying term means time-invariant.
● dy/dt term means dynamic which gives B → 1
Since, these options given only in code (C). So, no need to solve further.
Hence, alternative (C) is the correct choice.Correct Option: C
(A) 2t dy + 4y = 2tx dt
● Since, there is no constant hence linear.
● t factor means time-variant.
● dy/dt term means dynamic which gives A → 3
(B) y dy + 4y = 2x dt
● Since, there is no constant term mean linear
● No time varying term means time-invariant.
● dy/dt term means dynamic which gives B → 1
Since, these options given only in code (C). So, no need to solve further.
Hence, alternative (C) is the correct choice.
- The lengths of two discrete time sequences x1(n) and x2(n) are 5 and 7, respectively. What is the maximum length of a sequence x1(n) x2(n)?
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Given length of sequence
x1(n)= N1 = 5 and
given length of sequence
x2(n)= N2 = 7
Maximum length of sequence
x1(n) x2(n)= N1 + N2 – 1
= 5 + 7 – 1
= 11Correct Option: D
Given length of sequence
x1(n)= N1 = 5 and
given length of sequence
x2(n)= N2 = 7
Maximum length of sequence
x1(n) x2(n)= N1 + N2 – 1
= 5 + 7 – 1
= 11