Signal and systems miscellaneous
- A rectangular pulse of duration T is applied to a filter matched to this input. The output of the filter is a—
-
View Hint View Answer Discuss in Forum
NA
Correct Option: B
NA
- The Laplace transform of eat cos (αt) is equal to—
-
View Hint View Answer Discuss in Forum
Explanation can seen in synopsis on signals and systems.
Correct Option: A
Explanation can seen in synopsis on signals and systems.
- The energy for the signal—
x(n) = 3(0.5)2n n ≥ 0 will be—
-
View Hint View Answer Discuss in Forum
E = N – 1 |x(n)|2 ∑ n = 0 = ∞ |3(0.5)2n|2 ∑ n = 0 = 9 ∞ |3(.5)2|n ∑ n = 0 = 9 ∞ (.25)n ∑ n = 0
= 9[1 + (.25) + (.25)2 + (.25)3 + … ∞]= 9· 1 1 – .25
= 9· 1 = 12 1 – .75
Hence alternative (B) is the correct choice.Correct Option: B
E = N – 1 |x(n)|2 ∑ n = 0 = ∞ |3(0.5)2n|2 ∑ n = 0 = 9 ∞ |3(.5)2|n ∑ n = 0 = 9 ∞ (.25)n ∑ n = 0
= 9[1 + (.25) + (.25)2 + (.25)3 + … ∞]= 9· 1 1 – .25
= 9· 1 = 12 1 – .75
Hence alternative (B) is the correct choice.
- A linear phase channel with phase delay τp and group delay τg must have—
-
View Hint View Answer Discuss in Forum
For a linear phase channel phase delay should be directly proportional to the frequency and group delay should be constant.
Here alternative (D) is the correct choiceCorrect Option: D
For a linear phase channel phase delay should be directly proportional to the frequency and group delay should be constant.
Here alternative (D) is the correct choice
- Which of the following cannot be the Fourier series expansion of a periodic signal?
-
View Hint View Answer Discuss in Forum
To solve such type of problem solve each and every options one by one.
(A) x(t) = 2 cos 6t + 3 cos 3t
Fundamental period ofx1(t)= T1 = 2π = π 6 3
Fundamental period ofx2(t)= T2 = 2π = 2π 3 3
For the signal x(t) to be periodic ratio= rational number = π = T1 3 1 T2 2π 2 3
which is rational number
i.e., Fourier series expansion
(B) x(t) = 2 cos πt + 7 cos t
T1 = 2π = π = 2 ω π T1 = 2π = π = 2π ω 1 T1 = 2 = 1 = irrational numbers T2 2π π
i.e., Fourier series expansion is not possible.
Hence, alternative (B) is the correct choice, and no need to solve further other option.Correct Option: B
To solve such type of problem solve each and every options one by one.
(A) x(t) = 2 cos 6t + 3 cos 3t
Fundamental period ofx1(t)= T1 = 2π = π 6 3
Fundamental period ofx2(t)= T2 = 2π = 2π 3 3
For the signal x(t) to be periodic ratio= rational number = π = T1 3 1 T2 2π 2 3
which is rational number
i.e., Fourier series expansion
(B) x(t) = 2 cos πt + 7 cos t
T1 = 2π = π = 2 ω π T1 = 2π = π = 2π ω 1 T1 = 2 = 1 = irrational numbers T2 2π π
i.e., Fourier series expansion is not possible.
Hence, alternative (B) is the correct choice, and no need to solve further other option.