Volume and Surface Area of Solid Figures
- The perimeter of the triangular base of a right prism is 60 cm and the sides of the base are in the ratio 5 : 12 : 13. Then, its volume will be (height of the prism being 60 cm). ?
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Let the sides of the base are 5k, 12k and 13k, respectively.
Given, perimeter of base = 60 cm
⇒ 5k + 12k + 13k = 60Correct Option: A
Let the sides of the base are 5k, 12k and 13k, respectively.
Given, perimeter of base = 60 cm
⇒ 5k + 12k + 13k = 60
∴ k = 60/30 = 2
The sides of base are 10 cm, 24 cm 26 cm.
∴ Volume of prism = (1/2) x 10 x 24 x 50 = 6000 cm3
- A prism has the base a right angled triangle whose sides adjacent to the right angle are 10 cm and 12 cm long. The height of the prism is 20 cm. The density of the material of the prism is 6 g/cu cm. The weight of the prism is ?
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Volume of prism = Area of base x Height
Weight of prism = volume x densityCorrect Option: D
Volume of prism = Area of base x Height
= (1/2) x 10 x 12 x 20
= 1200 cm2
∴ Weight of prism = 1200 x 6
= 7200 g
= 7.2 kg
- If radius of a sphere is decreased by 24%, by what per cent does its surface area decrease ?
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According to the formula,
Percentage decrease in surface area = [2 x (-24) + (-24) x (-24)/100]%Correct Option: C
According to the formula,
Percentage decrease in surface area = [2 x (-24) + (-24) x (-24)/100]%
= [-48 + 5.76]% = - 42.24%
- If the radius of a sphere is increased by 3%, then what percent increase takes place in surface area of the sphere ?
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According to the formula
Percentage increase in surface area = [ 2x + x2/100]%Correct Option: A
According to the formula
Percentage increase in surface area = [ 2x + x2/100]%
= [2 x 3 + (3)2/100]%
= [6 + 0.09]%
= 6.09%
- The whole surface area of a rectangular block is 8788 sq cm. If length, breadth and height are in ratio of 4 : 3 : 2, then find the length. ?
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Let length, breadth and height be 4k, 3k and 2k, respectively.
Whole surface area = 2(lb + bh + lh)
⇒ (lb + bh + lh) = 8788/2 = 4394
⇒ (4 x 3 + 3 x 2 + 2 x 4 ) k2 = 4394Correct Option: B
Let length, breadth and height be 4k, 3k and 2k, respectively.
Whole surface area = 2(lb + bh + lh)
⇒ (lb + bh + lh) = 8788/2 = 4394
⇒ (4 x 3 + 3 x 2 + 2 x 4 ) k2 = 4394
⇒ 26k2 = 4394
⇒ k2 = 169
⇒ k = 13
∴ Length = 4k = 4 x 13 = 52 cm