Slant height (l) = √r² + h²
=√7² + 24²
= √49 + 576
= √625
= 25 cm
Curved surface area = πrl = (22/7) x 7 x 25 = 550 sq cm

Correct Option: B

Slant height (l) = √r² + h²
=√7² + 24²
= √49 + 576
= √625
= 25 cm
Curved surface area = πrl = (22/7) x 7 x 25 = 550 sq cm
∴ Area of 5 caps = 550 x 5 = 2750 sq cm

In first situation.
Radius = r₁, height = h₁ and volume = v₁

In second situation,
Radius =2r₁, height = h₂ and volume = v₂
In the volume is fixed, then
v₁ = v₂
⇒ (1/3)πr²₁h₁ = (1/3)π(2r₁)²h₂
⇒ h₁ = 4h₂

Correct Option: C

In first situation.
Radius = r₁, height = h₁ and volume = v₁

In second situation,
Radius =2r₁, height = h₂ and volume = v₂
In the volume is fixed, then
v₁ = v₂
⇒ (1/3)πr²₁h₁ = (1/3)π(2r₁)²h₂
⇒ h₁ = 4h₂
∴ h₂ = h₁/4
Therefore, height of the the cone will be one-fourth of the previous height.

Given, l = 9 m
and diameter = 14 m ⇒ r = 14/2 = 7 m
Now, volume = (1/3)πr²h
= (1/3)π x 49 x √l² - r²

Correct Option: A

Given, l = 9 m
and diameter = 14 m ⇒ r = 14/2 = 7 m
Now, volume = (1/3)πr²h
= (1/3)π x 49 x √l² - r²
= (1/3)π x 49 x √81 - 49
= (1/3) x 49π x √32 = 49π√32 /3 m³

[(1/3)πr₁²h₁]/[(1/3)πr₂²h₂] = 2/3
⇒ (r₁/r₂)² x (h₁/h₂) = 2/3

Correct Option: B

[(1/3)πr₁²h₁]/[(1/3)πr₂²h₂] = 2/3
⇒ (r₁/r₂)² x (h₁/h₂) = 2/3
⇒ (1/2)² x (h₁/h₂) = 2/3 [ &bacaus; r₁/r₂ = 1/2]
⇒ h₁/h₂ = 8/3
∴ h₁ : h₂ = 8 : 3

Let radius = 5k, height = 12k
According to the question
= 1/3 x 22/7 x (5k)² x 12k = 2200/7
⇒ k = 1
∴ r = 5, h = 12
∴ Slant height (l) = √r² + h²

Correct Option: B

Let radius = 5k, height = 12k
According to the question
= 1/3 x 22/7 x (5k)² x 12k = 2200/7
⇒ k = 1
∴ r = 5, h = 12
∴ Slant height (l) = √r² + h²
= √25 + 144
= √169
=13 cm