Given that, Height = 1 m
Diameter = 140 cm or 140/100 m = 1.40 m
∴ r = 1.40/2 = 0.7 m

Now,
Required sheet = Total surface area = 2πr( h + r)

Correct Option: A

Given that, Height = 1 m
Diameter = 140 cm or 140/100 m = 1.40 m
∴ r = 1.40/2 = 0.7 m

Now,
Required sheet = Total surface area = 2πr( h + r)
= (22/7) x 1.4 x (1 + 0.7) = 7.48 sq m
∴ Sheet required = 7.48 sq m

Given that, the height and radius of a right circular ,etal cone (solid) are 8 cm and 2 cm, respectively.
i.e., h = 8 cm and r = 2 cm
Let the radius of the sphere is R
Then, by condition,
1/3 π r² h = 4/3 π R³ h
⇒ 4 x 8 = 4 R³

Correct Option: A

Given that, the height and radius of a right circular ,etal cone (solid) are 8 cm and 2 cm, respectively.
i.e., h = 8 cm and r = 2 cm
Let the radius of the sphere is R
Then, by condition,
1/3 π r² h = 4/3 π R³ h
⇒ 4 x 8 = 4 R³
⇒ R³ = (2)³ = ⇒ R = 2
∴ Radius odf the sphere = 2 cm

Let the breadth and height of room be m and h m, respectively.
Then, according to the question, l x b = n x Area occupied by one patient
⇒ 14 x b = 56 x 22
∴ b = (56 x 22)/14 = 8.8 m³
∴ h x Area of occupied by one patient = 8.8

Correct Option: A

Let the breadth and height of room be m and h m, respectively.
Then, according to the question, l x b = n x Area occupied by one patient
⇒ 14 x b = 56 x 22
∴ b = (56 x 22)/14 = 8.8 m³
∴ h x Area of occupied by one patient = 8.8
h = 8.8/2.2
h = 4 m

r = Radius of the cone = 14/2 = 7 cm
h = Height of the cone = 12 x 2 = 24 cm
∴ Slant height (l) = √r² + h²
= √(7)² + (24)²
= √49 + 576
= √625
= 25 cm
Area of the sheet = Total surface area
= (πrl + πr²)

Correct Option: D

r = Radius of the cone = 14/2 = 7 cm
h = Height of the cone = 12 x 2 = 24 cm
∴ Slant height (l) = √r² + h²
= √(7)² + (24)²
= √49 + 576
= √625
= 25 cm
Area of the sheet = Total surface area
= (πrl + πr²)
= πr(l + r)
= (22/7) x 7 x (25 + 7) = 704 sq cm

Let length of the wire be h According to the question,
Volume of sphere = Volume of wire
(4/3) x π x 18 x 18 x 18 = π x (2/10) x (2/10) x h

Correct Option: D

Let length of the wire be h According to the question,
Volume of sphere = Volume of wire
(4/3) x π x 18 x 18 x 18 = π x (2/10) x (2/10) x h
∴ h = (100 x 1944) cm
= (100 x 1944)/100 m = 1944 m [∵ 1 cm = 1/100 m]