If the radius of a sphere is increased by 3%, then what

If the radius of a sphere is increased by 3%, then what percent increase takes place in surface area of the sphere ?

According to the formula
Percentage increase in surface area = [ 2x + x²/100]%
= [2 x 3 + (3)²/100]%
= [6 + 0.09]%
= 6.09%