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∵ a^{3} = 512 = 8 x 8 x 8
⇒ a = 8 cm
∵ Surface area = 6a^{2}
∵ a^{3} = 512 = 8 x 8 x 8
⇒ a = 8 cm
∵ Surface area = 6a^{2}
=[6 x (8)^{2}] cm^{2}
=384 cm^{2}
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Surface area = 6a2 = 726
Surface area = 6a^{2} = 726
⇒ a^{2} = 121
⇒ a = 11 cm
∴ Volume of the cube = (11 x 11 x 11) cm^{3}
= 1331 cm^{3}
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Let the edge of original cube = x cm
Edge of new cube = (2x) cm
Ratio of their volumes = x^{3} : (2x)^{3}
Let the edge of original cube = x cm
Edge of new cube = (2x) cm
Ratio of their volumes = x^{3} : (2x)^{3}
= x^{3} : 8x^{3}
= 1 :8
Thus the volumes be comes 8 times.
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Volume of new cube = (5)^{3} + (4)^{3} + (3)^{3} cm^{3}
Volume of new cube = (5)^{3} + (4)^{3} + (3)^{3} cm^{3}
= 126 cm^{3}
Edge of this cube = (6 x 6 x 6)^{1/3} = 6 cm
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Volume of new cube = [(5)^{3} + (4)^{3} + (3)^{3}] cm^{3}
Volume of new cube = [(5)^{3} + (4)^{3} + (3)^{3}] cm^{3}
= 216 cm^{3}
Edge of this cube = ( 6 x 6 x 6)^{1/3} = 6 cm
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