241. Given that   √3 = 3.6 and √130 = 11.4,   then the value of   √1.3 + √1300 + √0.013 is equal to

1. 1. 36.164

   
   
   

   2. 37.254

   
   
   

   3. 36.254

   
   
   

   4. 37.154

   
   
   

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1. View Hint View Answer Discuss in Forum

   √13 = 3.6 and √130 = 11.4
   ∴  √1.3 + √1300 + √0.013
   

   =	√	130	+ √13 × 100 +	√	130
   		100			10000

   
   

   =	11.4	+ 3.6 × 10 +	11.4
   	10		100

   
   = 1.14 + 36 + 0.114
   = 37.254

   Correct Option: B

   √13 = 3.6 and √130 = 11.4
   ∴  √1.3 + √1300 + √0.013
   

   =	√	130	+ √13 × 100 +	√	130
   		100			10000

   
   

   =	11.4	+ 3.6 × 10 +	11.4
   	10		100

   
   = 1.14 + 36 + 0.114
   = 37.254

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242. If √4096 = 64, then the value of √ 40.96 + √0.4096 +
     √0.004096 + √ 0.00004096 up to two places of decimals is :

1. 1. 7.09

   
   
   

   2. 7.10

   
   
   

   3. 7.11

   
   
   

   4. 7.12

   
   
   

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1. View Hint View Answer Discuss in Forum

   √4096 = 64
   ∴  √40.96 = 6.4 and
   √0.4096 = 0.64 etc.
   ∴  Expression
   = 6.4 + 0.64 + 0.064 + 0.0064
   = 7.1104

   Correct Option: C

   √4096 = 64
   ∴  √40.96 = 6.4 and
   √0.4096 = 0.64 etc.
   ∴  Expression
   = 6.4 + 0.64 + 0.064 + 0.0064
   = 7.1104

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243. The sum of the squares of 3 consecutive positive numbers is 365. The sum of the numbers is

1. 1. 30

   
   
   

   2. 33

   
   
   

   3. 36

   
   
   

   4. 45

   
   
   

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1. View Hint View Answer Discuss in Forum

   10² + 11² + 12²
   = 100 + 121 + 144 = 365
   ∴  Required sum = 10+11+12= 33

   Correct Option: B

   10² + 11² + 12²
   = 100 + 121 + 144 = 365
   ∴  Required sum = 10+11+12= 33

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244. √	48.4	is equal to
     	0.289

1. 1. 129	7
      	17

   
   
   

   2. 1	5
      	17

   
   
   

   3. 12	16
      	17

   
   
   

   4. 12	1
      	17

   
   
   

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1. View Hint View Answer Discuss in Forum

   √	48.4	=	√	48.4
   	0.289			2.89

   
   

   =	22	=	220	= 16	16
   	1.7		17		17

   Correct Option: C

   √	48.4	=	√	48.4
   	0.289			2.89

   
   

   =	22	=	220	= 16	16
   	1.7		17		17

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245. If √3 = 1.7321, the value of √192−	1	√48 −	√75
     	2

     ,5 correct to 3 places of decimal, is

1. 1. 8.661

   
   
   

   2. 4.331

   
   
   

   3. 1.7321

   
   
   

   4. –1.732

   
   
   

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1. View Hint View Answer Discuss in Forum

   Expression
   

   = √192 −	1	√48 −	√75
   	2

   
   

   = √64 × 3 −	1	√16 × 3 −	√25 × 3
   	2

   
   

   = 8√3 −	1	× 4√3 −	5√3
   	2

   
   = 8√3 − 2√3 − 5√3
   = √3 = 1.7321

   Correct Option: C

   Expression
   

   = √192 −	1	√48 −	√75
   	2

   
   

   = √64 × 3 −	1	√16 × 3 −	√25 × 3
   	2

   
   

   = 8√3 −	1	× 4√3 −	5√3
   	2

   
   = 8√3 − 2√3 − 5√3
   = √3 = 1.7321

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