Simplification


  1. Twenty one times of a positive number is less than its square by 100. The value of the positive number is









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    Suppose, the positive number be x.
    According to the question,
    x2 – 21x = 100
    ⇒  x2 – 21x – 100 = 0
    ⇒  x2 – 25x + 4x – 100 = 0
    ⇒  x (x – 25) + 4 (x – 25) = 0
    ⇒  (x – 25) (x + 4) = 0
    ⇒  x = 25 because x ≠ –4

    Correct Option: A

    Suppose, the positive number be x.
    According to the question,
    x2 – 21x = 100
    ⇒  x2 – 21x – 100 = 0
    ⇒  x2 – 25x + 4x – 100 = 0
    ⇒  x (x – 25) + 4 (x – 25) = 0
    ⇒  (x – 25) (x + 4) = 0
    ⇒  x = 25 because x ≠ –4


  1. The sum of two positive integers is 80 and the difference between them is 20. What is the difference between squares of those numbers ?









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    Let the numbers be x and y where x > y.
    ∴  x + y = 80
    x – y = 20
    ∴  (x + y) (x – y) = 80 × 20
    ⇒  x2 – y2 = 1600

    Correct Option: B

    Let the numbers be x and y where x > y.
    ∴  x + y = 80
    x – y = 20
    ∴  (x + y) (x – y) = 80 × 20
    ⇒  x2 – y2 = 1600



  1. The least six digit number which is a perfect square is









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    The smallest 6-digit number = 100000

    Clearly,
    316 < √100000 < 317
    317 × 317 = 100489
    ∴  Required number = 100489

    Correct Option: A

    The smallest 6-digit number = 100000

    Clearly,
    316 < √100000 < 317
    317 × 317 = 100489
    ∴  Required number = 100489


  1. The least number that must be subtracted from 63520 to make the result a perfect square is









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    Now, 63520 – 16 = 63504
    and √63504 = 252
    ∴  Required number = 16

    Correct Option: D


    Now, 63520 – 16 = 63504
    and √63504 = 252
    ∴  Required number = 16



  1. The difference between two numbers is 9 and the difference between their squares is 207. The numbers are :









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    Let the numbers be a and b where a > b.
    According to the question,
    a – b = 9 .... (i)
    and a2 – b2 = 207
    ⇒  (a + b) (a – b) = 207
    ⇒  9 (a + b) = 207

    ⇒  a + b =
    207
    = 23 .... (ii)
    9

    On adding equations (i) and (ii),
    a + b + a – b = 23 + 9
    ⇒  2a = 32 ⇒ a = 16
    ∴  a – b = 9
    ⇒  16 – b = 9
    ⇒  b = 16 – 9 = 7

    Correct Option: B

    Let the numbers be a and b where a > b.
    According to the question,
    a – b = 9 .... (i)
    and a2 – b2 = 207
    ⇒  (a + b) (a – b) = 207
    ⇒  9 (a + b) = 207

    ⇒  a + b =
    207
    = 23 .... (ii)
    9

    On adding equations (i) and (ii),
    a + b + a – b = 23 + 9
    ⇒  2a = 32 ⇒ a = 16
    ∴  a – b = 9
    ⇒  16 – b = 9
    ⇒  b = 16 – 9 = 7