Rate = (SI x 100) / (Principal x Time)

Correct Option: E

SI = 26350 - 21250 = ₹ 5100
∴ Rate = (SI x 100) / (Principal x Time)
= (5100 x 100) / (21250 x 6)
= 4%

Let sum = P, then SI = P/5 time = 10 yr.
∴ Rate = (100 x P)/(P x 5 x 10)

Correct Option: B

Let sum = P, then SI = P/5 time = 10 yr.
∴ Rate = (100 x P)/(P x 5 x 10) = 2%

Given, SI₂ = 60, SI₁ = 30, T₁ = 4 yr, T₂ = 8 yr

According to the question,
[(1500 x R x 8)/100] - [(1500 x R x 4)/100] = 60 - 30

Correct Option: C

Given, SI₂ = 60, SI₁ = 30, T₁ = 4 yr, T₂ = 8 yr
According to the question,
[(1500 x R x 8)/100] - [(1500 x R x 4)/100] = 60 - 30
⇒ (6000 x R)/100 = 30
∴ R = 30/60 = 1/2 = 0.5%

Here, n = 3, m = 2, T₁ = 20 yr
∴ T₂ = [(m -1) / (n - 1)] x T₁

Correct Option: B

Here, n = 3, m = 2, T₁ = 20 yr
∴ T₂ = [(m -1) / (n - 1)] x T₁
= (2 - 1) / (3 - 1) x 20 = 10 yr

Given, T₁ = 2¹/₂ yr, T₂ = 4 Yr

According to the question.
[P + (P x R x 4)/100] - [P + (P x R x 2.5)/100] = 1067.20 - 1012 = 55.2

For 4 yr.
SI = PRT/100 = (3680 x 4)/100 = ₹ 147.2

Correct Option: C

Given, T₁ = 2¹/₂ yr, T₂ = 4 Yr

According to the question.
[P + (P x R x 4)/100] - [P + (P x R x 2.5)/100] = 1067.20 - 1012 = 55.2
⇒ (1.5 x P x R)/100 = 55.2
⇒ PR = (552 x 100) / 15 = 3680

For 4 yr.
SI = PRT/100 = (3680 x 4)/100 = ₹ 147.2
∴ Sum (P) = 1067.2 - 147.2 = ₹ 920
We have, PR = 3680
∴ R = 3680/P = 3680/920 = 4%