Given, t = 8 yr, r = 3.5%, A = ₹ 364.80
Let amount = ₹ P
Since, A =P [1 + (RT/100)]

Correct Option: A

Given, t = 8 yr, r = 3.5%, A = ₹ 364.80
Let amount = ₹ P
Since, A =P [1 + (RT/100)]
∴ 364.80 = P[1 + (3.5 x 8)/100]
⇒ 364.80 = P[ 1+ (35 x 8)/100]
⇒ 3648/10 = P x (128/100)
⇒ P = 3648/128
= ₹ 285

SI = (P x R x T)/100

Correct Option: C

Let sum = P
Then, SI = (P x R x T)/100
= {P x (27/2) x 4} / 100
= {P x 54} / 100 = 27P / 50
∴ Amount = P + 27P / 50 = 77P/50
According to the question 77P/50 = 3080
∴ P = (3080 x 50)/77 = ₹ 2000

Here, P = ₹ 25800, R = 14%
T = 1 yr 4 months = 1 + (4/12) years = 1 + (1/3) = 4/3 yr.

According to the formula,
SI = (P x R x T) / 100

Correct Option: A

Here, P = ₹ 25800, R = 14%
T = 1 yr 4 months = 1 + (4/12) years = 1 + (1/3) = 4/3 yr.

According to the formula,
SI = (P x R x T) / 100 = {25800 x 14 x (4/3)}/100
= (258 x 14 x 4)/3
= ₹ 4816

Given, P = ₹ 8750., R = 7% T = 3 yr
According to the formula.
SI = (P x R x T)/100

Correct Option: B

Given, P = ₹ 8750., R = 7% T = 3 yr
According to the formula.
SI = (P x R x T)/100 = (8750 x 7 x 3)/100
= ₹ 1837.50

Here, P = ₹ 4000, R = 12¹/₂% = 25 / 2%
T = (24 + 31 + 18) days = 73 days
= 73/365 yr = 1/5 yr
∴ SI = (P x R x T)/100

Correct Option: D

Here, P = ₹ 4000, R = 12¹/₂% = 25 / 2%
T = (24 + 31 + 18) days = 73 days
= 73/365 yr = 1/5 yr
∴ SI = (P x R x T)/100 = (4000 x 25/2 x 1/5 )/100
= ₹ 100