S.I for 1 year = Rs. (925 - 850) = Rs. 75
S.I for 3 year = Rs. (75 x 3) = Rs. 225

Correct Option: C

S.I for 1 year = Rs. (925 - 850) = Rs. 75
S.I for 3 year = Rs. (75 x 3) = Rs. 225
∴ Sum = Rs. (850 - 225) = Rs. 625

S.I on Rs. 64 for 2 year = Rs. 19.20
∴ Rate = (100 x SI) / (P x T) = (100 x 19.20) / (64 x 2) = 15%
∴ S.I On Rs. 86 for 4 year = (P x R x T) / 100 = Rs. (86 x 4 x 15 ) /100 = Rs.51.60

Correct Option: A

S.I on Rs. 64 for 2 year = Rs. 19.20
∴ Rate = (100 x SI) / (P x T) = (100 x 19.20) / (64 x 2) = 15%
∴ S.I On Rs. 86 for 4 year = (P x R x T) / 100 = Rs. (86 x 4 x 15 ) /100 = Rs.51.60
∴ Amount of Rs. 86 after 4 years = Rs. (86 + 51.60) = Rs. 137.60

S.I. for 1 year = Rs. (783 - 702) = Rs 81
S.I. for 2 years = Rs. (81 x 2) = Rs. 162
∴ Sum = Rs. (702 - 162) = Rs. 540
∴ Required rate = = (100 x SI) / (P x T) = (100 x 162) / (540 x 2) % = 15%

Correct Option: D

S.I. for 1 year = Rs. (783 - 702) = Rs 81
S.I. for 2 years = Rs. (81 x 2) = Rs. 162
∴ Sum = Rs. (702 - 162) = Rs. 540
∴ Required rate = = (100 x SI) / (P x T) = (100 x 162) / (540 x 2) % = 15%

Rate = (Interest x 100) / (Principal x Time)

Correct Option: C

Rate = (Interest x 100) / (Principal x Time)
= (800 x 100) / (8000 x 2)
= 5%

Let 'P' is the principal
SI= (P x R x T)/100
where , SI= Simple Interest
T= Time
R= Rate

Correct Option: C

Rate of Interest = 12% per annum
Simple Interest =Rs 6000 per annum
Let 'P' is the principal
SI= (P x R x T)/100
where , SI= Simple Interest
T= Time
R= Rate

∴ 6000=(P x 1 x 12)/100
∴ P =(6000 x 100)/12
= Rs 50000
Hence the required amount is Rs 50000