Ratio, Proportion


  1. How many sides does a regular polygon have whose interior and exterior angles are in the ratio 2 : 1?









  1. View Hint View Answer Discuss in Forum

    Let interior angle = I and exterior angle = E
    According to questions,

    I
    =
    2
    ⇒ 2E = I.1 or, E =
    I
    E12

    But I + E = 180°
    I +
    I
    = 180
    2

    3
    I = 180
    2

    I =
    2
    × 180
    3

    I = 120°
    We know that each interior angle of a regular polygon of n sides is given by
    I =
    n − 2
    × 180°
    n

    120° =
    n − 2
    × 180°
    n

    ⇒ 
    n − 2
    =
    120°
    =
    2
    n180°3

    ⇒  3n – 6 = 2n ⇒ n = 6

    Correct Option: C

    Let interior angle = I and exterior angle = E
    According to questions,

    I
    =
    2
    ⇒ 2E = I.1 or, E =
    I
    E12

    But I + E = 180°
    I +
    I
    = 180
    2

    3
    I = 180
    2

    I =
    2
    × 180
    3

    I = 120°
    We know that each interior angle of a regular polygon of n sides is given by
    I =
    n − 2
    × 180°
    n

    120° =
    n − 2
    × 180°
    n

    ⇒ 
    n − 2
    =
    120°
    =
    2
    n180°3

    ⇒  3n – 6 = 2n ⇒ n = 6


  1. ₹ 600 is divided among A, B and C. ₹ 40 more than (2/5)th of A’ share, ₹ 20 more than (2/7)th of B’s share and ₹ 10 more than (9/17)th of C’s share are all equal. Then A’s share is









  1. View Hint View Answer Discuss in Forum

    According to the question,
    A + B + C = 600 .... (i)
    and

    2A
    + 40 =
    2B
    + 20 =
    9C
    + 10
    5717

    ∴ 
    2A
    + 40 =
    2B
    + 20
    57

    =
    2A
    + 20 =
    2
    B
    57

    ∴  B =
    7
    2A
    + 20 =
    7A
    + 70
    255

    Again,  
    2A
    + 40 =
    9C
    + 10
    517

    ⇒ 
    9C
    =
    2A
    + 30
    175

    ⇒  C =
    17
    2A
    + 30
    95

    =
    34A
    +
    170
    453

    ∴  A +
    7A
    + 70 =
    34A
    +
    170
    = 600
    5453

    ⇒  A +
    7A
    +
    34A
    = 600 − 70 −
    170
    5453

    ⇒ 
    45A + 63A + 34A
    45

    = 530 −
    170
    3

    ⇒ 
    142A
    =
    1590 − 170
    =
    1420
    4533

    ⇒  A =
    1420
    ×
    45
    3142

    = Rs. 150

    Correct Option: A

    According to the question,
    A + B + C = 600 .... (i)
    and

    2A
    + 40 =
    2B
    + 20 =
    9C
    + 10
    5717

    ∴ 
    2A
    + 40 =
    2B
    + 20
    57

    =
    2A
    + 20 =
    2
    B
    57

    ∴  B =
    7
    2A
    + 20 =
    7A
    + 70
    255

    Again,  
    2A
    + 40 =
    9C
    + 10
    517

    ⇒ 
    9C
    =
    2A
    + 30
    175

    ⇒  C =
    17
    2A
    + 30
    95

    =
    34A
    +
    170
    453

    ∴  A +
    7A
    + 70 =
    34A
    +
    170
    = 600
    5453

    ⇒  A +
    7A
    +
    34A
    = 600 − 70 −
    170
    5453

    ⇒ 
    45A + 63A + 34A
    45

    = 530 −
    170
    3

    ⇒ 
    142A
    =
    1590 − 170
    =
    1420
    4533

    ⇒  A =
    1420
    ×
    45
    3142

    = Rs. 150



  1. A, B and C invested ₹ 13,000, ₹ 17,000 and ₹ 5,000 respectively in a business. At the end of the year, they earn a profit of ₹ 1,400. B’s share of profit is









  1. View Hint View Answer Discuss in Forum

    Ratio of the equivalent capitals of A, B and C for 1 month
    = 13000 × 12 : 17000 × 12 : 5000 × 12
    = 13 : 17 : 5
    Sum of the terms of ratio
    = 13 + 17 + 5 = 35
    Total profit = Rs. 1400

    ∴  B’s share = Rs.
    17
    × 1400 = Rs. 680
    35

    Correct Option: A

    Ratio of the equivalent capitals of A, B and C for 1 month
    = 13000 × 12 : 17000 × 12 : 5000 × 12
    = 13 : 17 : 5
    Sum of the terms of ratio
    = 13 + 17 + 5 = 35
    Total profit = Rs. 1400

    ∴  B’s share = Rs.
    17
    × 1400 = Rs. 680
    35


  1. ₹ 1980 is divided among A, B and C so that half of A’s part, one-third of B’s part and onesixth of C’s part are equal. Then B’s part is









  1. View Hint View Answer Discuss in Forum

    According to the question,

    A
    =
    B
    =
    C
    236

    ∴  A : B : C = 2 : 3 : 6
    Sum of the terms of ratio
    = 2 + 3 + 6 = 11
    Total amount = Rs. 1980
    ∴  B’s share = Rs.
    3
    × 1980 = Rs. 450
    11

    Correct Option: A

    According to the question,

    A
    =
    B
    =
    C
    236

    ∴  A : B : C = 2 : 3 : 6
    Sum of the terms of ratio
    = 2 + 3 + 6 = 11
    Total amount = Rs. 1980
    ∴  B’s share = Rs.
    3
    × 1980 = Rs. 450
    11



  1. A sum of Rs. 15525 is divided among Sunil, Anil and Jamil such that if Rs. 22, Rs. 35 and Rs. 48 be diminished from their shares respectively, their remaining sums shall be in the ratio 7 : 10 : 13. What would have been the ratio of their sums if Rs. 16, Rs. 77 and Rs. 37 respectively were added to their original shares?









  1. View Hint View Answer Discuss in Forum

    According to the question,
    Amount to be distributed in the ratio 7 : 10 : 13
    = Rs. (15525 – 22 – 35 – 45)
    = Rs. 15420
    Sum of the terms of ratio
    = 7 + 10 + 13 = 30

    Sunil’s share = Rs.
    7
    × 15420 = Rs. 3598
    30

    Anil’s share = Rs.
    10
    × 15420 = Rs. 5140
    30

    Jamil’s share = Rs.
    13
    × 15420 = Rs. 6682
    30

    Ratio after respective increase in each share
    = (3598 + 22 + 16) : (5140 + 35 + 77) : (6682 + 48 + 37)
    = 3636 : 5252 : 6767
    = 36 : 52 : 67

    Correct Option: C

    According to the question,
    Amount to be distributed in the ratio 7 : 10 : 13
    = Rs. (15525 – 22 – 35 – 45)
    = Rs. 15420
    Sum of the terms of ratio
    = 7 + 10 + 13 = 30

    Sunil’s share = Rs.
    7
    × 15420 = Rs. 3598
    30

    Anil’s share = Rs.
    10
    × 15420 = Rs. 5140
    30

    Jamil’s share = Rs.
    13
    × 15420 = Rs. 6682
    30

    Ratio after respective increase in each share
    = (3598 + 22 + 16) : (5140 + 35 + 77) : (6682 + 48 + 37)
    = 3636 : 5252 : 6767
    = 36 : 52 : 67