Ratio, Proportion
- A person ordered 4 shirts of brand A and some shirts of brand B. The price of one shirt of brand A was twice that of brand B. When the order was executed, it was found that the numbers of the two brands has been interchanged. This increased the bill by 40%. The ratio of the number of brand A shirts to that of brand B shirts in the original order was
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Let the number of shirts of brand B be x.
Let the cost of a shirt of brand B be ₹ 1.
∴ Original cost = 4 × 2 + x = ₹ (8 + x)
In case II,4 + 2x = (8 + x) × 140 = (8 + x) 7 100 5
⇒ 20 + 10x = 56 + 7x
⇒ 10x – 7x = 56 – 20 = 36
⇒ 3x = 36 ⇒ x = 12
∴ Required ratio = 4 : 12 = 1 : 3Correct Option: B
Let the number of shirts of brand B be x.
Let the cost of a shirt of brand B be ₹ 1.
∴ Original cost = 4 × 2 + x = ₹ (8 + x)
In case II,4 + 2x = (8 + x) × 140 = (8 + x) 7 100 5
⇒ 20 + 10x = 56 + 7x
⇒ 10x – 7x = 56 – 20 = 36
⇒ 3x = 36 ⇒ x = 12
∴ Required ratio = 4 : 12 = 1 : 3
- From each of the two given unequal numbers, half the smaller number is subtracted. Then, of the resulting numbers, the larger one is five times than the smaller one. Then the ratio of the larger to smaller one is
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let the numbers be x and y where x > y.
∴ x − y = 5 y − y = 5y 2 2 2 ⇒ x = y + 5y = 3y ⇒ x = 3 2 2 y 1 Correct Option: C
let the numbers be x and y where x > y.
∴ x − y = 5 y − y = 5y 2 2 2 ⇒ x = y + 5y = 3y ⇒ x = 3 2 2 y 1
- Three persons walk from place A to place B. Their speeds are in the ratio 4 :3 : 5. The ratio of the time taken by them to reach B will be :
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Time taken is inversely proportional to relevant speeds.
∴ Required ratio = 1 : 1 : 1 4 3 5 = 1 × 60 : 1 × 60 : 1 × 60 4 3 5
= 15 : 20 : 12Correct Option: C
Time taken is inversely proportional to relevant speeds.
∴ Required ratio = 1 : 1 : 1 4 3 5 = 1 × 60 : 1 × 60 : 1 × 60 4 3 5
= 15 : 20 : 12
- The ratio of the first and second class fares between two railway stations is 4 : 1 and that of the number of passengers travelling by first and second classes is 1 : 40. If on a day ₹ 1,100 are collected as total fare, the amount collected from the first class passengers is
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Ratio of the first and second class fares (total)
= 1 × 4 : 1 × 40
= 4 : 40 = 1 : 10
∴ Amount collected from the first class passengers= 1 × 1100 = ₹ 100 11 Correct Option: D
Ratio of the first and second class fares (total)
= 1 × 4 : 1 × 40
= 4 : 40 = 1 : 10
∴ Amount collected from the first class passengers= 1 × 1100 = ₹ 100 11
- A sum of ₹ 340.68 is distributed among L, M and N such that L gets ₹ 5.72 more than N and M gets Rs. 2.24 more than L. N gets
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L = N + 5.72
M = L + 2.24
= N + 5.72 + 2.24
M = N + 7.96
L + M + N = 340.68
N + 5.72 + N + 7.96 + N
= 340.68 ⇒ 3N = 327
⇒ 3N = 327⇒ N = 327 = ₹ 109 3 Correct Option: A
L = N + 5.72
M = L + 2.24
= N + 5.72 + 2.24
M = N + 7.96
L + M + N = 340.68
N + 5.72 + N + 7.96 + N
= 340.68 ⇒ 3N = 327
⇒ 3N = 327⇒ N = 327 = ₹ 109 3