Pipes and Cistern


  1. A pipe can empty a tank in 40 minutes. A second pipe with diameter twice as much as that of the first is also attached with the tank to empty it. The two together can empty the tank in :









  1. View Hint View Answer Discuss in Forum

    As per the given in question ,
    Here, the diameter of the second pipe is twice that of first pipe.
    ∴ Volume of water emptied by the second pipe will be 4 times to that of first pipe.
    Hence, time taken will be 1/4 of the first pipe.

    ∴ Second pipe will empty the tank in
    1
    × 40 = 10 minutes
    4

    When both the pipes are open, the part of the tank emptied in
    1 minute =
    1
    +
    1
    =
    1 + 4
    =
    1
    4010408

    Correct Option: A

    As per the given in question ,
    Here, the diameter of the second pipe is twice that of first pipe.
    ∴ Volume of water emptied by the second pipe will be 4 times to that of first pipe.
    Hence, time taken will be 1/4 of the first pipe.

    ∴ Second pipe will empty the tank in
    1
    × 40 = 10 minutes
    4

    When both the pipes are open, the part of the tank emptied in
    1 minute =
    1
    +
    1
    =
    1 + 4
    =
    1
    4010408

    Hence, the tank will be emptied in 8 minutes.


  1. Two pipes can fill a tank with water in 15 and 12 hours respectively and a third pipe can empty it in 4 hours. If the pipes be opened in order at 8, 9 and 11 a.m. respectively, the tank will be emptied at









  1. View Hint View Answer Discuss in Forum

    On the basis of given details in question ,

    Part filled by A from 8 a.m to 11 a.m. =
    3
    =
    1
    155

    Part filled by B from 9 a.m. to 11 a.m. =
    2
    =
    1
    126

    Total Part filled till 11 a.m. =
    1
    +
    1
    =
    6 + 5
    =
    11
    563030

    At 11 a.m. pipe C is opened to empty it.
    ∴ Part of tank emptied in 1 hour =
    1
    -
    1
    -
    1
    41512

    Part of tank emptied in 1 hour =
    15 - 4 - 5
    =
    1
    6010

    Correct Option: A

    On the basis of given details in question ,

    Part filled by A from 8 a.m to 11 a.m. =
    3
    =
    1
    155

    Part filled by B from 9 a.m. to 11 a.m. =
    2
    =
    1
    126

    Total Part filled till 11 a.m. =
    1
    +
    1
    =
    6 + 5
    =
    11
    563030

    At 11 a.m. pipe C is opened to empty it.
    ∴ Part of tank emptied in 1 hour =
    1
    -
    1
    -
    1
    41512

    Part of tank emptied in 1 hour =
    15 - 4 - 5
    =
    1
    6010

    11
    part will be emptied in
    11
    × 10 =
    11
    hours or 3
    2
    303033

    i.e. 3 hours 40 minutes or at 11 : 40 a.m.
    Therefore , the tank will be emptied at 11 : 40 a.m.



  1. A Boy and girl together fill a cistern with water. The boy pours 4 litres of water every 3 minutes and the girl pours 3 litres every 4 minutes. How much time will it take to fill 100 litres of water in the cistern ?









  1. View Hint View Answer Discuss in Forum

    On the basis of given details in question ,

    Water filled by the boy in 1 minute =
    4
    3

    Water filled by a girl in 1 minute =
    3
    4

    Water filled by the boy and girl in 1 minute =
    4
    +
    3
    =
    16 + 9
    =
    25
    litres
    341212

    Correct Option: C

    On the basis of given details in question ,

    Water filled by the boy in 1 minute =
    4
    3

    Water filled by a girl in 1 minute =
    3
    4

    Water filled by the boy and girl in 1 minute =
    4
    +
    3
    =
    16 + 9
    =
    25
    litres
    341212

    ∴ Time taken to fill 100 litres =
    100
    × 12 = 48 minutes
    25


  1. A pipe of diameter d can drain a certain water tank in 40 minutes. The time taken by a pipe of diameter 2d for doing the same job in :









  1. View Hint View Answer Discuss in Forum

    As we know that ,

    Time α
    1
    cross sectional area of the pipe

    Time α
    1
    π
    4

    Time α
    1

    t2
    =
    (d1
    t1(d2

    [Being inversely related]
    t2 = t1
    d1
    ²
    d2

    t1 = 40 minutes, d1 = d, d2 = 2d

    Correct Option: B

    As we know that ,

    Time α
    1
    cross sectional area of the pipe

    Time α
    1
    π
    4

    Time α
    1

    t2
    =
    (d1
    t1(d2

    [Being inversely related]
    t2 = t1
    d1
    ²
    d2

    t1 = 40 minutes, d1 = d, d2 = 2d
    ∴t2 = 40
    d
    ²
    2d

    t2 = 40
    1
    ²
    2

    Hence , t2 = 10 minutes



  1. Two pipes A and B can fill a water tank in 20 and 24 minutes respectively and a third pipe C can empty at the rate of 3 gallons per minute. If A, B and C are opened together to fill the tank in 15 minutes, the capacity (in gallons) of the tank is :









  1. View Hint View Answer Discuss in Forum

    Let the capacity of the tank be q gallons.
    When all the pipes A, B and C are opened simultaneously

    Quantity of water filled in the tank in 1 minute =
    q
    +
    q
    - 3
    2024

    According to the question ,
    q
    +
    q
    - 3 =
    q
    202415

    q
    +
    q
    -
    q
    = 3
    202415

    Correct Option: C

    Let the capacity of the tank be q gallons.
    When all the pipes A, B and C are opened simultaneously

    Quantity of water filled in the tank in 1 minute =
    q
    +
    q
    - 3
    2024

    According to the question ,
    q
    +
    q
    - 3 =
    q
    202415

    q
    +
    q
    -
    q
    = 3
    202415

    6q + 5q - 8q
    = 3
    120

    ⇒ 3 q = 3 × 120
    ⇒ q =
    3 × 120
    = 120 gallons
    3